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In the trial and error method, different values are substituted until the equation is satisfied.
Equality is maintained when the same operation is performed on both sides.
4x = 28, so x = 7.
Add 18 to both sides to get 9m = 63. Hence, m = 7.
Multiply both sides by 8 to get y = 88.
2a = 18, so a = 9.
Addition is undone by subtraction.
Divide by 6 to get p – 2 = 5. Therefore, p = 7.
7x + 5 = 54 ⇒ 7x = 49 ⇒ x = 7.
Substituting x = 4 satisfies only option (d).
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