The displacement of a particle is represented by the equation . The motion of the particle is
simple harmonic with period
periodic but not simple harmonic
non-periodic
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As given that,
Velocity of the particle
So, acceleration,
In simple harmonic motion acceleration (or force) is directly proportional to the negative of displacement of particle as acceleration,
Hence, due to negative sign motion is simple harmonic motion (SHM.)
A simple harmonic motion is always periodic. So motion is periodic simple harmonic.
From the given equation,
Compare it by standard equation
So,
Hence, the motion is SHM with period .
The displacement of a particle is represented by the equation . The motion is
The relation between acceleration and displacement of four particles are given below. Which, one of the particle is exempting simple harmonic motion?
For motion to be SHM acceleration of the particle must be opposite of restoring force and proportional to negative of displacement. So, i.e., , so
Hence,
We should be clear that has to be linear.
Motion of an oscillating liquid column in a U-tube is
simple harmonic and time period is independent of the density of the liquid
simple harmonic and time period is directly proportional to the density of the liquid
Consider a U-tube filled in which a liquid column oscillates. When liquid column lifted upto height from to in arm . The liquid level in arm becomes at , so the difference between the height of two columns are .
In this case, restoring force acts on the liquid due to gravity. Acceleration of the liquid column, can be calculated in terms of restoring force.
Restoring force,
Weight of liquid column of height
Equilibrium level
As restoring force at opposite to gravitational force as liquid is lifted against
Then so motion is SHM.
Time period
Time period is independent of the density of the liquid and motion is harmonic.
A particle is acted simultaneously by mutually perpendicular simple harmonic motion and . The trajectory of motion of the particle will be
an ellipse
a parabola
a circle
a straight line
The resultant-displacement can be find by adding and -components.
According to variation of and , trajectory will be predicted, so resultant displacement is
So, the displacement is not straight line and not parabola also. Now, squaring and adding eqs. (i) and (ii),
This is the equation of a circle, so motion in circular (independent of time).
Clearly, the locus is a circle of constant radius .
The displacement of a particle varies with time according to the relation .
The motion is oscillatory but not SHM
The motion is SHM with amplitude
smaller than and is larger than .
If is given a transverse displacement,
will vibrate with maximum amplitude
All the four will oscillate with equal amplitude
When pendulum vibrate with transverse vibration then
length of pendulum.
Through the elastic rigid support the disturbance is transferred to all the pendulum and are having length and hence same frequency. They will be in resonance, because their time period of oscillation.
So, a periodic force of period produces resonance in and and they will vibrate with maximum amplitude as in resonance.
Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and
the initial position are indicated on the figure. The simple harmonic motion of the -projection of the
radius vector of the rotating particle is
The equation of motion of a particle is . The motion is
periodic but not oscillatory
periodic and oscillatory
oscillatory but not periodic
neither periodic nor oscillatory
According to the question,
is a cosine function, so it is an oscillatory motion.
Now, at, . The equation of motion of particle
where, is supposed as period of the function .
Hence, it is oscillatory but not periodic.
A particle executing SHM maximum speed of and a maximum acceleration of . The period of oscillation is
Let us consider a equation of an SHM is represented by
(given) ...(i)
Acceleration
Eqs. (i) and (ii), we get
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