A charge of is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be:
and
0 and
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Let distance between the two divided charges be r.
From Coulomb's law, force between two charge,
For to be maximum,
Two point charges each are placed at a distance apart. A third point charge is placed at a distance from midpoint on the perpendicular bisector. The value of at which charge will experience the maximum Coulomb's force is :
The figure shows a charge at point held in equilibrium in air with the help of four charges situated at the vertices of a square: The net electrostatic force on is given by
Newton's
Coulomb's law
Principle of superposition
Net electric flux out the position of .
The weight of the charge hold in air is in equillibrium with net electrostatic force exerted by the four charges situated at the corners. The net electrostatic force is given by the vector sum of the individual forces exerted by the charges at the corners. This is principle of superposition.
Which of the following graphs shows the correct variation of force when the distance between two charges varies?
From Coulomb's law i.e., which is correctly shown by graph (d).
The force of repulsion between two electrons at a certain distance is F. The force between two protons separated by the same distance is
Electrostatic force is given by
Here, charge and distance are same. So, force between two protons will be same.
The force between two small charged spheres having charges of and placed apart in air is
Here, and ,
Two insulated charged metalic sphere and have their centres separated by a distance of . The radii of and are negligible compared to the distance of separation. The mutual force of electrostatic repulsion if the charge on each is is
Here Electrostatic force,
If a charge is placed at the centre of the line joining two equal charges such that the system is in equilibrium then the value of is
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