Two identical charged spheres suspended from a common point by two massless strings of lengths , are initially at a distance apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity . Then varies as a function of the distance between the spheres, as :
Get Answer
From figure
or
Differentiating eq. (i) w.r.t. time
but is constant so Replace from eq. (ii)
Suppose the charge of a proton and an electron differ slightly. One of them is , the other is . If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance (much greater than atomic size) apart is zero, then is of the order of.[Given mass of hydrogen ]
According to question, the net electrostatic force gravitational force
An electron falls from rest through a vertical distance in a uniform and vertically upward directed electric field . The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance . The time of fall of the electron, in comparison to the time of fall of the proton is
smaller
5 times greater.
equal
10 times greater
As we know,
i.e., time as ' ' is same for electron and proton.
Since, electron has smaller mass so it will take smaller time.
Two point charges and ; having charges and respectively, are placed at certain distance apart and force acting between them is . If charge of is transferred to , then force between the charges becomes:
We know that,
If of charges of A transfer to then
and
Two parallel infinite line charges with linear charge densities and are placed at a distance of in free space. What is the electric field mid-way between the two line charges?
zero
Electric field due to line charge (1)
Electric field due to line charge (2)
[Note: Both and are in the same direction.]
A spherical conductor of radius has a charge of 3.2 distributed uniformly. What is the magnitude of electric field at a point from the centre of the sphere?
If the charge on a spherical conductor of radius is , then electric field at distance from centre is
(if )
Electric field at a distance from the centre of sphere will be
Polar molecules are the molecules
having a permanent electric dipole moment
having zero dipole moment
acquire a dipole moment only in the presence of electric field due to displacement of charges
acquire a dipole moment only when magnetic field is absent
In polar molecules, like the centre of positive charges does not coincide with the centre of negative charges.
Hence, permanent electric dipole exists
Two point charges and are placed at a distance of , as shown in the figure. The magnitude of electric field intensity at a distance varies as:
If it will be have like a dipole and in dipole we have,
An electric dipole is placed at an angle of with an electric field of intensity . It experiences a torque equal to . Calculate the magnitude of charge on the dipole, if the dipole length is .
Given and
Charge on the dipole,
If over a surface, then
The number of flux lines entering the surface must be equal to the number of flux lines leaving it
The magnitude of electric field on the surface is constant
All the charges must necessarily be inside the surface
The electric field inside the surface is necessarily uniform
Since,
i.e., Net flux throfigh surface is zero, so number of flux lines entering the surface must be equal to the number of flux lines leaving it.
General Knowledge
Academics Question Bank
PHYSICS
CHEMISTRY
BIOLOGY
MATHEMATICS
THE WORLD AROUND US
HISTORY
GEOGRAPHY
CIVICS
ECONOMICS
Physics
How - Why - What
NCERT Books (Class 1-12)
Learn At Your Own Pace... Because, Everyone's Pace of Learning is Different...
A unit of Innovexcel Edu Solution LLP.
SWIFT, RELIABLE & CONVENIENT..
Social Media
Corporate Office : Bharat Impact Building, C-26, Sector - 59, Noida, Uttar Pradesh - 201301, India
Excel With Tutors : A Perfect Tutoring Platform & Repository of Learning Materials. Matches the Best Tutor as Per Your Requirement.
© 2025 | ©Innovexcel Edu Solution LLP. All Rights Reserved.
Technology Partner: Indev Consultancy Pvt Ltd