EWT | Academic Question

Questions
Question (1)
QN0038923
  1. A parallel plate capacitor with plate area  and plate separation  has a capacitance of . The new capacitance of the system if half of the space between them is filled with a dielectric material of dielectric constant  (as shown in figure) will be:                                                                                                             

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

We have,

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Question (2)
QN0038924

A capacitor plates are charged by a battery with '  ' volts. After charging battery is disconnected and a dielectric slab with dielectric constant '  ' is inserted between its plates, the potential across the plates of a capacitor will become                 

  • (A)

    Zero

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

Battery is disconnected.

Charge remains context


 

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Question (3)
QN0038925

A parallel plate air capacitor has a capacitance of . The plates are at a distance  apart. If a slab of thickness  ) and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be

  • (A)

        

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

Capacitance will increase but not 5 times (because dielectric is not filled completely). Hence, new capacitance may be .

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Question (4)
QN0038926

A parallel plate capacitor having a separation between the plates , plate area  and material with dielectric constant  has capacitance . Now one-third of the material is replaced by another material with dielectric constant , so that effectively there are two capacitors one with area , dielectric constant and another with area  and dielectric constant . If the capacitance of this new capacitor is  then  is           

  • (A)

    1

  • (B)

  • (C)

  • (D)

Correct Answer: B
Explanation:

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Question (5)
QN0038927

A parallel plate cápacitor with air between the plates is charged to a potential difference of  and then insulated. A plastic plate is inserted between the plates filling the whole gap. The potential difference between the plates now becomes 75V. The dielectric constant of plastic is

  • (A)

  • (B)

    5

  • (C)

  • (D)

    10

Correct Answer: C
Explanation:

By definition,

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Question (6)
QN0038928

Two parallel plate capacitors of capacitance  and  are connected in parallel and charged to a potential difference . The battery is then disconnected, and the region between the plates of  is filled completely with a material of dielectric constant . The common potential difference across the combination becomes 

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: D
Explanation:

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Question (7)
QN0038929

An uncharged paralle plate capacitor having a dielectric of dielectric constant  is connected to a similar air cored parallel plate capacitor charged to a potential . The two share the charge, and the common potential becomes . The dielectric constant  is

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

and

We know that

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Question (8)
QN0038930

A parallel plate capacitor with air between the plates is charged to a potential difference of  and then insulated.
A plastic plate is inserted between the plates filling the whole gap. The potential difference between the plates now becomes . The dielectric constant of plastic is              

  • (A)

  • (B)

    5

  • (C)

  • (D)

    10

Correct Answer: C
Explanation:

By definition, 

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Question (9)
QN0038931

A parallel-plate capacitor is filled by a dielectric whose permittivity varies with the applied voltage according to the law , where . The same (but containing no dielectric) capacitor charged to a voltage  is connected in parallel to the first "nonlinear" uncharged capacitor. Determine the final voltage  across the capacitors.

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: B
Explanation:

The capacitance of the nonlinear capacitor is

where  is the capacitance of the capacitor without a dielectric. The charge on the nonlinear capacitor is , while the charge on the normal capacitor is . It follows from the charge conservation law  that the required voltage is .

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