EWT | Academic Question

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Question (11)
QN006772
Alpha particles used in Rutherford’s experiment are —
  • (A) Negatively charged
  • (B) Neutral
  • (C) Positively charged
  • (D) Uncharged atoms

Correct Answer: C
Explanation:

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Question (12)
QN006773
The gold foil experiment is also called —
  • (A) Cathode ray experiment
  • (B) Alpha-ray scattering experiment
  • (C) Electron diffraction experiment
  • (D) Proton emission experiment

Correct Answer: B
Explanation:

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Question (13)
QN006774
Most alpha particles passed through the gold foil without deflection because —
  • (A) Gold atoms are soft
  • (B) Atoms contain large empty space
  • (C) Alpha particles are very light
  • (D) Nucleus attracts them

Correct Answer: B
Explanation:

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Question (14)
QN006775
A few alpha particles were sharply deflected in Rutherford’s experiment because —
  • (A) Electrons absorbed them
  • (B) Positive charge is concentrated in nucleus
  • (C) Gold foil melted
  • (D) Alpha particles became neutral

Correct Answer: B
Explanation:

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Question (15)
QN006776
Rutherford proposed that electrons revolve around the nucleus like —
  • (A) Fish in water
  • (B) Planets around the Sun
  • (C) Birds around nest
  • (D) Clouds around mountain

Correct Answer: B
Explanation:

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Question (16)
QN006777
Rutherford’s model is also known as the —
  • (A) Plum pudding model
  • (B) Planetary model
  • (C) Wave model
  • (D) Orbital model

Correct Answer: B
Explanation:

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Question (17)
QN006778
The approximate diameter of an atom according to Rutherford is —
  • (A) 10^-5 m
  • (B) 10^-8 m
  • (C) 10^-10 m
  • (D) 10^-15 m

Correct Answer: C
Explanation:

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Question (18)
QN006779
The approximate diameter of a nucleus is —
  • (A) 10^-5 m
  • (B) 10^-10 m
  • (C) 10^-12 m
  • (D) 10^-15 m

Correct Answer: D
Explanation:

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Question (19)
QN006780
If an atom were the size of a cricket ground, Rutherford compared the nucleus to a —
  • (A) Football
  • (B) Grain of sand
  • (C) Black pepper grain
  • (D) Marble

Correct Answer: C
Explanation:

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Question (20)
QN006781
A sheet has thickness 10^-4 m. If one atom has diameter 10^-10 m, the number of atoms stacked is approximately —
  • (A) 10^2
  • (B) 10^4
  • (C) 10^6
  • (D) 10^8

Correct Answer: C
Explanation:

Divide 10^-4 by 10^-10.

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