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Question (21)

QN004730

A glass tumbler gains 10 g of water due to condensation over 5 equal intervals. Average gain per interval is

(A) 1 g
(B) 2 g
(C) 3 g
(D) 5 g

Correct Answer: B

Explanation:

10 ÷ 5 = 2 g

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Question (22)

QN004731

If mass readings at 0 min and 30 min are 250 g and 262 g respectively, total condensed water collected is

(A) 10 g
(B) 11 g
(C) 12 g
(D) 13 g

Correct Answer: C

Explanation:

262 − 250 = 12 g

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Question (23)

QN004732

A student marks the water level inside a tumbler. After 30 minutes, the level remains unchanged while droplets collect outside. This proves that

(A) water is seeping out
(B) glass is absorbing water
(C) condensation is occurring outside
(D) ice is escaping

Correct Answer: C

Explanation:

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Question (24)

QN004733

The increase in mass during Activity 8.4 occurs because

(A) glass absorbs moisture
(B) water vapour from air condenses on the tumbler
(C) ice becomes heavier
(D) steel plate expands

Correct Answer: B

Explanation:

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Question (25)

QN004734

A setup gains 15 g of condensed water in 30 minutes. What is the average gain per minute?

(A) 0.25 g
(B) 0.5 g
(C) 1 g
(D) 1.5 g

Correct Answer: B

Explanation:

15 ÷ 30 = 0.5 g/min

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Question (26)

QN004735

If condensation adds 18 g in 6 equal time intervals, each interval contributes

(A) 2 g
(B) 3 g
(C) 4 g
(D) 6 g

Correct Answer: B

Explanation:

18 ÷ 6 = 3 g

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Question (27)

QN004736

A balance reading increases from 720 g to 732 g. Fractional increase in mass is

(A) 1/60
(B) 1/50
(C) 1/40
(D) 1/30

Correct Answer: A

Explanation:

Increase = 12 g; 12/720 = 1/60

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Question (28)

QN004737

A tumbler gains 9 g due to condensation. If this represents 3% of the initial mass, the initial mass was

(A) 200 g
(B) 250 g
(C) 300 g
(D) 350 g

Correct Answer: C

Explanation:

9 = 3% of mass; Mass = 9 × 100 ÷ 3 = 300 g

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Question (29)

QN004738

If water vapour condenses at a rate of 2 g every 5 minutes, how much condenses in 30 minutes?

(A) 8 g
(B) 10 g
(C) 12 g
(D) 14 g

Correct Answer: C

Explanation:

30 min = 6 intervals; 6 × 2 = 12 g

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Question (30)

QN004739

A setup weighs 480 g initially and 492 g after condensation. The percentage increase is

(A) 1.5%
(B) 2%
(C) 2.5%
(D) 5%

Correct Answer: C

Explanation:

(12/480) × 100 = 2.5%

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Question (21)

A glass tumbler gains 10 g of water due to condensation over 5 equal intervals. Average gain per interval is

Explanation:

Link:

Question (22)

If mass readings at 0 min and 30 min are 250 g and 262 g respectively, total condensed water collected is

Explanation:

Link:

Question (23)

A student marks the water level inside a tumbler. After 30 minutes, the level remains unchanged while droplets collect outside. This proves that

Explanation:

Link:

Question (24)

The increase in mass during Activity 8.4 occurs because

Explanation:

Link:

Question (25)

A setup gains 15 g of condensed water in 30 minutes. What is the average gain per minute?

Explanation:

Link:

Question (26)

If condensation adds 18 g in 6 equal time intervals, each interval contributes

Explanation:

Link:

Question (27)

A balance reading increases from 720 g to 732 g. Fractional increase in mass is

Explanation:

Link:

Question (28)

A tumbler gains 9 g due to condensation. If this represents 3% of the initial mass, the initial mass was

Explanation:

Link:

Question (29)

If water vapour condenses at a rate of 2 g every 5 minutes, how much condenses in 30 minutes?

Explanation:

Link:

Question (30)

A setup weighs 480 g initially and 492 g after condensation. The percentage increase is

Explanation:

Link:

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