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Diagonals of a parallelogram bisect each other. Equating the midpoints of AC and BD gives p = 7.
All four sides are equal and the adjacent sides are perpendicular, so the quadrilateral is a square.
All four sides are equal, while the diagonals are unequal. Hence the quadrilateral is a rhombus.
AB = 5, BC = 5 and AC = 8. Hence AB = BC, so the triangle is isosceles.
AB² = 3²+4² = 25 and BC² = 4²+(−3)² = 25. Therefore AB²+BC² = 50.
AB = 5, BC = 5 and AC = 6. Therefore the side lengths are 5,5,6.
61 = 6²+(y−3)², so (y−3)²=25 and y=8 or −2.
P = ((1×8+2×2)/3, (1×9+2×3)/3) = (4,5).
x=8 and y=7 from the midpoint formula. Therefore x+y=15.
Ratio 1:1 means P is the midpoint. P = ((2+8)/2,(4+10)/2) = (5,7).
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