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P(defective) = 6/120 = 1/20.
Acceptable shirts = 120 − 6 = 114. P = 114/120 = 0.95.
Good bulbs = 18 − 3 = 15. P(good) = 15/18 = 5/6.
Initially there are 16 good bulbs. After removing one good bulb, 15 good bulbs remain out of 19. P = 15/19.
There are 12 multiples of 5 from 1 to 60. P = 12/60 = 1/5.
Perfect squares are 1, 4, 9, 16, 25, 36 and 49. P = 7/50.
Favourable numbers are 5 and 7. P = 2/8 = 1/4.
Two of the six faces are marked A. P(A) = 2/6 = 1/3.
P(loss) = 1 − P(win) = 1 − 0.68 = 0.32.
All same outcomes are HHH and TTT, so P(win) = 2/8 = 1/4. Therefore P(lose) = 3/4.
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