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Adding the two equations: first + second = S and first − second = D gives 2 × first = S + D
Second = (S − D)/2 = (4 − 12)/2 = −4
Swapping first and second number changes first − second to second − first, reversing the sign
−10 + 3 = −7 and −10 − 3 = −13, both conditions satisfied
5 + x = −2 gives x = −7
Leftward movements are represented as negative integers
For the final position a + (−b) to be positive, a must be greater than b
Second = (S − D)/2 = (−7 − (−1))/2 = −6/2 = −3
6 × (−2) = −12
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