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Question (31)

QN0018990

Which number is divisible by 2, 3, 5 and 10 simultaneously?

(A) 128
(B) 990
(C) 275
(D) 1586

Correct Answer: B

Explanation:

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Question (32)

QN0018991

The sum of digits of 639210 is:

(A) 20
(B) 21
(C) 22
(D) 23

Correct Answer: B

Explanation:

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Question (33)

QN0018992

Therefore, 639210 is divisible by:

(A) 3 only
(B) 9 only
(C) Both 3 and 7
(D) 3 but not 9

Correct Answer: D

Explanation:

Digit sum = 21.

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Question (34)

QN0018993

Which of the following numbers is divisible by 8?

(A) 2856
(B) 275
(C) 1586
(D) 6686

Correct Answer: A

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Question (35)

QN0018994

The number 275 is divisible by:

(A) 2
(B) 3
(C) 5
(D) 8

Correct Answer: C

Explanation:

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Question (36)

QN0018995

If the difference of alternating digit sums is 0, the number is:

(A) Divisible by 3
(B) Divisible by 9
(C) Divisible by 11
(D) Divisible by 8

Correct Answer: C

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Question (37)

QN0018996

Which of the following numbers is NOT divisible by 11?

(A) 990
(B) 90904
(C) 857076
(D) 3060

Correct Answer: D

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Question (38)

QN0018997

The divisibility rule for 3 depends on:

(A) Product of digits
(B) Sum of digits
(C) Last digit
(D) First digit

Correct Answer: B

Explanation:

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Question (39)

QN0018998

If the sum of digits of a number is 36, the number is definitely divisible by:

(A) 4 and 8
(B) 3 and 9
(C) 5 and 10
(D) 11 and 22

Correct Answer: B

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Question (40)

QN0018999

Which statement is always true?

(A) Every number divisible by 9 is divisible by 3.
(B) Every number divisible by 3 is divisible by 9.
(C) Every even number is divisible by 8.
(D) Every multiple of 11 is a multiple of 9.

Correct Answer: A

Explanation:

Every multiple of 9 is also a multiple of 3.

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