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Question (21)

QN003291

Velocity changes from 5 m/s to 15 m/s in 5 s. Acceleration equals

(A) 1 m/s²
(B) 2 m/s²
(C) 3 m/s²
(D) 4 m/s²

Correct Answer: B

Explanation:

a = (15−5)/5 = 2 m/s²

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Question (22)

QN003292

Velocity decreases from 20 m/s to 0 in 4 s. Retardation equals

(A) 2 m/s²
(B) 5 m/s²
(C) 10 m/s²
(D) 80 m/s²

Correct Answer: B

Explanation:

a = (0−20)/4

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Question (23)

QN003293

Area under v–t graph equals 60 m for 12 s motion. Average velocity is

(A) 2 m/s
(B) 5 m/s
(C) 10 m/s
(D) 12 m/s

Correct Answer: B

Explanation:

v = displacement/time

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Question (24)

QN003294

A body moving at constant velocity 10 m/s for 8 s travels

(A) 18 m
(B) 40 m
(C) 80 m
(D) 800 m

Correct Answer: C

Explanation:

s = vt

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Question (25)

QN003295

A triangular region under v–t graph with base 6 s and height 12 m/s gives displacement

(A) 18 m
(B) 36 m
(C) 72 m
(D) 144 m

Correct Answer: B

Explanation:

Area = ½ × base × height

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Question (26)

QN003296

Velocity–time graph passing through origin indicates

(A) initial velocity zero
(B) infinite velocity
(C) constant acceleration zero
(D) constant displacement

Correct Answer: A

Explanation:

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Question (27)

QN003297

Decreasing slope in velocity–time graph indicates

(A) positive acceleration
(B) negative acceleration
(C) zero acceleration
(D) constant displacement

Correct Answer: B

Explanation:

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Question (28)

QN003298

A curved velocity–time graph represents

(A) uniform acceleration
(B) variable acceleration
(C) constant velocity
(D) rest

Correct Answer: B

Explanation:

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Question (29)

QN003299

Equal areas under velocity–time graphs over same time imply equal

(A) acceleration
(B) displacement
(C) velocity
(D) speed

Correct Answer: B

Explanation:

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Question (30)

QN003300

A body starting from rest reaches 20 m/s in 10 s. Distance travelled equals

(A) 50 m
(B) 100 m
(C) 200 m
(D) 400 m

Correct Answer: B

Explanation:

Area of triangle = ½ × 10 × 20

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Question (21)

Velocity changes from 5 m/s to 15 m/s in 5 s. Acceleration equals

Explanation:

Link:

Question (22)

Velocity decreases from 20 m/s to 0 in 4 s. Retardation equals

Explanation:

Link:

Question (23)

Area under v–t graph equals 60 m for 12 s motion. Average velocity is

Explanation:

Link:

Question (24)

A body moving at constant velocity 10 m/s for 8 s travels

Explanation:

Link:

Question (25)

A triangular region under v–t graph with base 6 s and height 12 m/s gives displacement

Explanation:

Link:

Question (26)

Velocity–time graph passing through origin indicates

Explanation:

Link:

Question (27)

Decreasing slope in velocity–time graph indicates

Explanation:

Link:

Question (28)

A curved velocity–time graph represents

Explanation:

Link:

Question (29)

Equal areas under velocity–time graphs over same time imply equal

Explanation:

Link:

Question (30)

A body starting from rest reaches 20 m/s in 10 s. Distance travelled equals

Explanation:

Link:

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