EWT | Academic Question

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Question (31)
QN006042
A sound wave has intensity 18 W/m² across area 3 m². Find energy crossing in 5 s.
  • (A) 54 J
  • (B) 90 J
  • (C) 180 J
  • (D) 270 J

Correct Answer: D
Explanation:

Energy = 18 × 3 × 5 = 270 J

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Question (32)
QN006043
Which unit is commonly used to express loudness level?
  • (A) Newton
  • (B) Pascal
  • (C) Decibel
  • (D) Joule

Correct Answer: C
Explanation:

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Question (33)
QN006044
Excessive loud sound can damage
  • (A) kidneys
  • (B) vocal cords only
  • (C) eardrums
  • (D) bones only

Correct Answer: C
Explanation:

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Question (34)
QN006045
Noise pollution mainly results from
  • (A) moderate pleasant sounds
  • (B) excessive unwanted sounds
  • (C) low intensity sound only
  • (D) ultrasonic waves only

Correct Answer: B
Explanation:

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Question (35)
QN006046
Which of the following is an effective method to reduce noise pollution?
  • (A) Increasing loudspeaker volume
  • (B) Planting trees
  • (C) Removing silencers from vehicles
  • (D) Using metal walls everywhere

Correct Answer: B
Explanation:

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Question (36)
QN006047
Sound intensity level is measured using
  • (A) thermometer
  • (B) ammeter
  • (C) sound level meter
  • (D) barometer

Correct Answer: C
Explanation:

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Question (37)
QN006048
A sound wave carries 90 J through 3 m² area in 5 s. Calculate intensity.
  • (A) 3 W/m²
  • (B) 6 W/m²
  • (C) 9 W/m²
  • (D) 15 W/m²

Correct Answer: B
Explanation:

Intensity = 90/(3 × 5) = 6 W/m²

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Question (38)
QN006049
The loudness of sound perceived by humans depends on
  • (A) sensitivity of ear
  • (B) colour of source
  • (C) magnetic field
  • (D) atmospheric pressure only

Correct Answer: A
Explanation:

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Question (39)
QN006050
If amplitude becomes three times, energy becomes
  • (A) three times
  • (B) six times
  • (C) nine times
  • (D) twenty-seven times

Correct Answer: C
Explanation:

Energy ∝ amplitude²

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Question (40)
QN006051
A sound source emits 400 J energy in 20 s over area 5 m². Intensity is
  • (A) 2 W/m²
  • (B) 4 W/m²
  • (C) 8 W/m²
  • (D) 20 W/m²

Correct Answer: B
Explanation:

Intensity = 400/(20 × 5) = 4 W/m²

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