EWT | Academic Question

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Question (11)
QN006152
Megaphones work on the principle of
  • (A) refraction of sound
  • (B) absorption of sound
  • (C) multiple reflection of sound
  • (D) magnetic effect of sound

Correct Answer: C
Explanation:

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Question (12)
QN006153
Stethoscope works mainly due to
  • (A) refraction of sound
  • (B) multiple reflection of sound
  • (C) dispersion of sound
  • (D) diffraction of sound

Correct Answer: B
Explanation:

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Question (13)
QN006154
The repeated reflection of sound in a large hall resulting in persistence of sound is called
  • (A) echo
  • (B) reverberation
  • (C) refraction
  • (D) diffraction

Correct Answer: B
Explanation:

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Question (14)
QN006155
Excessive reverberation in auditoriums can be reduced by using
  • (A) marble walls
  • (B) metal sheets
  • (C) sound absorbing materials
  • (D) glass surfaces only

Correct Answer: C
Explanation:

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Question (15)
QN006156
A reflected sound heard separately from the original sound is called
  • (A) vibration
  • (B) resonance
  • (C) echo
  • (D) pitch

Correct Answer: C
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Question (16)
QN006157
A person hears an echo 2 seconds after shouting. If speed of sound is 340 m/s, the reflector is at a distance of
  • (A) 170 m
  • (B) 340 m
  • (C) 510 m
  • (D) 680 m

Correct Answer: B
Explanation:

Distance = vt/2 = 340 × 2 / 2 = 340 m

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Question (17)
QN006158
A sound wave travels 1020 m in 3 seconds during reflection experiment. Speed of sound is
  • (A) 170 m/s
  • (B) 300 m/s
  • (C) 340 m/s
  • (D) 680 m/s

Correct Answer: C
Explanation:

Speed = distance/time = 1020/3 = 340 m/s

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Question (18)
QN006159
Which surface is best suited for sound reflection?
  • (A) Curtains
  • (B) Foam
  • (C) Concrete wall
  • (D) Carpet

Correct Answer: C
Explanation:

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Question (19)
QN006160
The minimum time gap between original sound and reflected sound to distinguish echo is
  • (A) 0.01 s
  • (B) 0.05 s
  • (C) 0.1 s
  • (D) 0.5 s

Correct Answer: C
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Question (20)
QN006161
A child claps near a hill and hears echo after 3 seconds. Distance of hill from child is
  • (A) 255 m
  • (B) 340 m
  • (C) 510 m
  • (D) 1020 m

Correct Answer: C
Explanation:

Distance = vt/2 = 340 × 3 / 2 = 510 m

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