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Increase in speed increases kinetic energy
v = √(2KE/m) = √(500/5) = 10 m/s
Zero work means no change in kinetic energy
KE = ½ × 0.02 × 100² = 100 J
Loss in kinetic energy means negative work
Work done changes kinetic energy
Initial KE = 6 J, final KE = 6 + 24 = 30 J
Final KE = 100 – 40 = 60 J
KE = ½ × 10 × 2² = 20 J
Kinetic energy depends on square of velocity
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