EWT | Academic Question

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Question (41)
QN006222
A coolie walks 30 m carrying a load on his head. The upward force applied by him is 500 N. Work done by this upward force is:
  • (A) 15000 J
  • (B) 500 J
  • (C) Zero
  • (D) –15000 J

Correct Answer: C
Explanation:

Force and displacement are perpendicular

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Question (42)
QN006223
Which example represents positive work done?
  • (A) Brakes stopping a car
  • (B) Friction slowing a ball
  • (C) Lifting a suitcase upward
  • (D) Holding a bag stationary

Correct Answer: C
Explanation:

Force and displacement are in same direction

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Question (43)
QN006224
A force of 18 N does 90 J of work. The displacement produced is:
  • (A) 108 m
  • (B) 5 m
  • (C) 72 m
  • (D) 0.2 m

Correct Answer: B
Explanation:

s = 90 ÷ 18 = 5 m

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Question (44)
QN006225
A child pulls a sled with a constant force. If both force and displacement double, the work done becomes:
  • (A) Double
  • (B) Four times
  • (C) Half
  • (D) Same

Correct Answer: B
Explanation:

Work becomes 2 × 2 = 4 times

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Question (45)
QN006226
The scientific reason why a person feels tired while pushing a wall despite doing zero work on it is that:
  • (A) Gravity acts strongly
  • (B) Muscles use internal energy
  • (C) Wall stores energy
  • (D) Air resistance increases

Correct Answer: B
Explanation:

Muscles consume energy internally

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Question (46)
QN006227
A force of 250 N acts opposite to displacement of 2 m. The work done by the force equals:
  • (A) 500 J
  • (B) –500 J
  • (C) 125 J
  • (D) Zero

Correct Answer: B
Explanation:

W = –250 × 2 = –500 J

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Question (47)
QN006228
In a force-displacement graph, if force is constant at 20 N from 0 m to 3 m, the work done is:
  • (A) 60 J
  • (B) 23 J
  • (C) 17 J
  • (D) 600 J

Correct Answer: A
Explanation:

Area = 20 × 3 = 60 J

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Question (48)
QN006229
A woman slowly lifts a 100 N object vertically upward through 1.5 m. Work done by her is:
  • (A) 150 J
  • (B) 15 J
  • (C) 66.7 J
  • (D) 250 J

Correct Answer: A
Explanation:

W = 100 × 1.5 = 150 J

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Question (49)
QN006230
Exact definition: “The work done on an object by a constant force” equals:
  • (A) Force × acceleration
  • (B) Force × velocity
  • (C) Force applied × displacement in the direction of force
  • (D) Mass × displacement

Correct Answer: C
Explanation:

Standard definition of work done

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Question (50)
QN006231
A person pulls a luggage bag with a force of 35 N for 14 m in the direction of motion. Calculate the work done.
  • (A) 490 J
  • (B) 49 J
  • (C) 2.5 J
  • (D) 21 J

Correct Answer: A
Explanation:

W = 35 × 14 = 490 J

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