As we go down below the earth's surface, the acceleration due to gravity decreases by a factor distance, radius of earth)
remains constant
Get Answer
Acceleration due to gravity varies with dpth as
The weight of a body at the centre of the earth is
zero
infinite
same as on the surface of earth
None of these
weight of the body at the centre of the earth is zero, because the value of at centre is zero.
The variation of acceleration due to gravity with distance (r) from the center of the earth is correctly represented by: (Given = radius of earth)
A particle is suspended from a spring and it stretches the spring by on the surface of earth. By how much amount the same particle will stretch the same spring at a place above the surface of earth.
The height at which the acceleration due to gravity becomes (where the acceleration due to gravity on the surface of the earth) in terms of , the radius of the earth, is
We know that
At what height from the ground will the value of be the same as that in deep mine below the surface of earth?
If a person goes to height equal to the radius of the earth, from its surface, then his weight relative to the weight on earth (W) will be
If value of acceleration due to gravity is ' ' at a height 50 above the surface of earth, then at what depth inside the earth will the acceleration due to gravity be same as ' '?
As we know,
The gravitational field strength due to a solid sphere (mass , radius ) varies with distance from centre as
for and for so option (a) is correct.
There are gravitational lines of force inside a spherically symmetric shell.
infinitely many
Zero
varying number depending upon surface area
varying number depending upon volume
There is no gravitational field in the shell.
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