Minimum force required on a block of weight for motion along rough horizontal surface of coefficient of friction is
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The retarding acceleration of due to frictional force stops the car of mass travelling on a road. The coefficient of friction between the tyre of the car and the road is
0.55
0.75
0.70
0.65
As we know, coefficient of
friction
given
A block A of mass is placed on another block B of mass , and the block B rests on a smooth horizontal table. If the minimum force that can be applied on so that both the blocks move together is , the maximum force that can be applied to for the blocks to move together will be
Minimum force on
= frictional force between the surfaces
Therefore maximum acceleration
Hence maximum force, total mass
The two blocks, and are free to move as shown. The coefficient of static friction between the blocks is 0.5 and there is no friction between and the ground. A minimum horizontal force is applied to hold against that is equal to
As would slip in vertically downward direction, then
Newton
Same normal force would accelerated ,
thus
Taking as system
A given object takes times as much time to slide down a rough incline as it takes to slide down a perfectly smooth incline. The coefficient of friction between the object and the incline is
A small mass slides down a fixed inclined plane of inclination with the horizontal. The coefficient of friction is where is the distance through which the mass slides down and is a constant. Then the speed is maximum after the mass covers a distance of
Acceleration of mass at distance
Speed is maximum, when
What is the maximum value of the force such that the block shown in the arrangement, does not move?
A block of mass is placed on a plank of mass which is placed on a smooth horizontal plane. The coefficient of friction between the block and the plank is . If a horizontal force is applied on the plank, then find the maximum value of for which the block and the plank move together. (Take )
None of the above
For no slipping between and ,
For no toppling of block
In figure, block 1 is one-fourth the length of block 2 and weighs one-fourth as much. Assume that there is no friction between block 2 and the surface on which it moves and that the coefficient of sliding friction between blocks 1 and 2 is . After the system is released find the distance block 2 has moved when only one-fourth of block 1 still on block 2. Block 1 and block 3 have the same mass.
Two identical smooth surfaced solid cylinders of radius are placed touching along their lengths on a horizontal surface. A third cylinder of same material but twice the radius of that of the cylinders is placed lengthwise on them so that the system remains at rest. If all three cylinders have the same length, then minimum value of the coefficient of friction between smaller cylinders and the surface is:
None of these
If mass of smaller cylinder is , then mass of bigger one will be . For the equilibrium of upper cylinder,
Now for the equilibrium of lower cylinder,
and
or
After solving above equations, we get
.
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