The dependence of velocity of a body with time is given by the equation . The body is in
uniform retardation
uniform acceleration
non-uniform acceleration
zero acceleration.
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On differentiating, acceleration
The deceleration experienced by a moving motorboat after its engine is cut off, is given by where is constant. If is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time after the cut-off is
The displacement of a particle as a function of time is shown in figure. It indicates that
the velocity of the particle is constant throughout
the acceleration of the particle is constant throughout
the particle starts with a constant velocity and is accelerated
the motion is retarded and finally the particle stops
From displacement-time graph, it is clear that in equal intervals of time displacements are not equal infact, decreases and after 40s displacement constant i.e., the particle stops.
A particle moves along a straight line . At a time (in second) the distance (in metre) of the particle from is given by . How long would the particle travel before coming to rest?
.
When particle comes to rest,
Therefore distance travelled by particle before coming to rest,
A particle moves a distance in time according to equation . The acceleration of particle is proportional to
(velocity)3/2
(distance)
(velocity)
Now
A particle is moving eastwards with a velocity of . In 10 seconds the velocity changes to northwards. The average acceleration in this time is
towards north
towards north - east
towards north – west
zero
Average acceleration
Avg. acc.
which means is in the second quadrant. (towards northwest)
It is given that , where is displacement and is time. The acceleration of particle at origin is
Differentiate two times and put .
An object, moving with a speed of , is decelerated at a rate given by: where is the instantaneous speed. The time taken by the object, to come to rest, would be
0
1
2
3
-2
6
16
Which of the following describes the motion correctly?
there is not enough data for generalization
At
Thus,
and
After solving equations, we get .
Now for ,
Clearly it represents motion with constant acceleration.
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