The equation of SHM is , then its phase at time ' ' is
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phase at time,
The displacement of a particle in simple harmonic motion in one time period is amplitude
Zero
As seen from figure after one time period the bob return to its equilibrium position, so diplacement of the particle is zero, but distance covered by the particle in one time period is (where is amplitude of bob, when it does S.H.M.)
The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
zero
Let
Acceleration
Which of the following is a simple harmonic motion?
Particle moving through a string fixed at both ends.
Wave moving through a string fixed at both ends.
Earth spinning about its axis.
Ball bouncing between two rigid vertical walls.
The displacement vs time of a particle executing SHM is shown in figure. The initial phase is
For , we have
or .
So for .
Two particles are executing simple harmonic motion of the same amplitude and frequency along the -axis. Their mean position is separated by distance . If the maximum separation between them is , the phase difference between their motion is
Let and
The resultant motion can be treated as a simple harmonic motion with amplitude .
Given, maximum distance between the particles Amplitude of resultant S.H.M.
.
Two simple harmonic motions are represented by the equations and . The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is
Phase diff.
Motion of a particle in plane is described by a set of following equations and . The path of particle will be-
circular
helical
parabolic
elliptical
So, , which is equation of circle.
If a particle takes to reach position of minimum velocity from previous such position, then
A simple harmonic motion has an amplitude and time period . The time required by it to travel from to is
At extreme position
Now then
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