EWT | Academic Question

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Question (1)
QN0035322

The wide handle of screw is based upon        

  • (A)

    Newton's second law of motion

  • (B)

    law of conservation of linear momentum

  • (C)

    turning moment of force

  • (D)

    None of these

Correct Answer: C
Explanation:

Turning moment of force  Force  distance from the axis of rotation.

Thus a small force is required to produce a given turning moment, when distance is large: That is why handle of a screw is made wider.

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Question (2)
QN0035323

Which of the following is an expression for angular momentum?

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: D
Explanation:

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Question (3)
QN0035324

The torque of a force  about the origin is . If the force acts on a particle whose position vector is , then the value of  will be :

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

Given that torque,

Position vector,

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Question (4)
QN0035325

When a mass is rotating in a plane about a fixed point, its angular momentum is directed along the

  • (A)

    radius of orbit 

  • (B)

    tangent to the orbit

  • (C)

    line parallel to plane of rotation

  • (D)

    line perpendicular to plane of rotation

Correct Answer: D
Explanation:

As angular momentum, , therefore, direction of  is along a line perpendicular to the plane of rotation.

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Question (5)
QN0035326

A particle moving in a circular path has an angular momentum of . If the frequency of rotation is halved, then its angular momentum becomes

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

Angular momentum of particle is given by:

If frequency is halved then,

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Question (6)
QN0035327

The instantaneous angular position of a point on a rotating wheel is given by the equation . The torque on the wheel becomes zero at 

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

 When angular acceleration  is zero then torque on the wheel becomes zero.

.

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Question (7)
QN0035328

A force  is acting at a point . The value of  for which angular momentum about origin is conserved is

  • (A)

    2

  • (B)

    zero

  • (C)

     1

  • (D)

    -1

Correct Answer: D
Explanation:

From Newton's second law for rotational motion,

, if  constant then

So,

Solving we get

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Question (8)
QN0035329

A particle of mass  is on a smooth horizontal table and moves in a circular path of radius . The height of the table from the ground is . If the angular speed of the particle is , the magnitude of its angular momentum about a point on the ground right under the centre of the circle is

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

Angular momentum,

[As ,  ]

So,

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Question (9)
QN0035330

If the angular momentum of a particle of mass  rotating along a circular path of radius  with uniform speed is , the centripetal force acting on the particle is

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

From the relation, angular momentum, 

Centripetal force acting on the particle

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Question (10)
QN0035331

A stone of mass  tied to a string of length  is rotating along a circular path with constant speed . The torque on the stone is

  • (A)

  • (B)

  • (C)

  • (D)

    zero

Correct Answer: D
Explanation:

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