For which of the following does the centre of mass lie outside the body?
A pencil
A shotput
A dice
A bangle
Get Answer
A bangle is in the form of a ring as shown in figure. The centre of mass of the ring lies at its centre, which is outside the ring or bangle.
A
B
C
D
Centre of mass of a system lies towards the part of the system, having bigger mass. In the above diagram, lower part is heavier, hence of the system lies below the horizontal diameter at point.
The initial velocity is and after reflection from the wall, the final velocity is . The trajectory is at constant distance on axis and as particle moves along axis, its component changes .
So position vector (moving along -axis),
Hence, the change in angular momentum is .
When a disc rotates with uniform angular velocity, which of following is not true?
The sense of rotation remains same
The orientation of the axis of rotation remains same
The speed of rotation is non-zero and remains same
The angular acceleration is non-zero and remains same
Angular acceleration where is angular velocity of the disc and is uniform or constant.
Hence, angular acceleration is zero:
increased
decreased
the same
changed in unpredicted manner
According to the question, when the small piece removed it is stick at through axis of rotation passes, but axis of rotation does not passes through and It is glued to the centre of the plate, the mass comes closer to the axis, hence, moment of inertia decreases.
In problem-5, the of the plate is now in the following quadrant of - plane.
i
ii
iii
iv
(c) Let us consider the diagram of problem 5 , there is a line shown in the figure drawn along the diagonal. First, centre of mass of the system was on the dotted line and was shifted towards from the centre (1st quadrant).
When the mass is decrease, it will be on the same line but shifted towards other side of on the line-joining or away from the centre so, new will lies in IIIrd quadrant in plane.
The density of a non-uniform rod of length is given by where, and are constants and . The centre of mass of the rod will be at
As given that density :
where and are constants and
At constant
In that case, centre of mass will be at (i.e., mid-point of the rod)
Putting, in options.(a) (b) (c) (d)
So, only (a) option gives 0.5 .
A merry-go-round, made of a ring-like platform of radius and mass , is revolving with angular speed . A person of mass is standing on it. At one instant, the person jumps off the round, radially away from the centre of the round (as seen from the round). The speed of the round of afterwards is
0
As there is external torque acting on the system, angular momentum should be conserved.
Hence constant
where, is moment of inertia of the system and is angular velocity of the system.
From Eq. (i),
where and are angular velocities before and after jumping.
So, given that,
?
as mass reduced to half, hence, moment of inertia also reduced to half:
General Knowledge
Academics Question Bank
PHYSICS
CHEMISTRY
BIOLOGY
MATHEMATICS
THE WORLD AROUND US
HISTORY
GEOGRAPHY
CIVICS
ECONOMICS
Physics
How - Why - What
NCERT Books (Class 1-12)
Learn At Your Own Pace... Because, Everyone's Pace of Learning is Different...
A unit of Innovexcel Edu Solution LLP.
SWIFT, RELIABLE & CONVENIENT..
Social Media
Corporate Office : Bharat Impact Building, C-26, Sector - 59, Noida, Uttar Pradesh - 201301, India
Excel With Tutors : A Perfect Tutoring Platform & Repository of Learning Materials. Matches the Best Tutor as Per Your Requirement.
© 2025 | ©Innovexcel Edu Solution LLP. All Rights Reserved.
Technology Partner: Indev Consultancy Pvt Ltd