The first operation involved in a Carnot cycle is
isothermal expansion
adiabatic expansion
isothermal compression
adiabatic compression
Get Answer
First operation in carnot cycle is isothermal expansion.
Which of the following statements is incorrect?
All reversible cycles have same efficiency
Reversible cycle has more efficiency than an irreversible one
Carnot cycle is a reversible one
Carnot cycle has the maximum efficiency in all cycles
A Carnot engine works between a source and a sink maintained at constant temperatures and .
For efficiency to be the greatest
and should be high
and should be low
should be low and should be high
should be high and should be low
So for be high must be high and must be low:
The efficiency of a Carnot engine operating between the temperatures of and will be
The temperature of source and sink of a heat engine are and respectively. An inventor
claims its efficiency to be , then:
it is impossible
it is possible with high probability
it is possible with low probability
data are insufficient.
Hence, it is not possible to have efficiency more than .
Even Carnot engine cannot give efficiency because we cannot
prevent radiation
find ideal sources
reach absolute zero temperature
eliminate friction
Absolute zero temperature is practically not reachable.
If the temperatures of source and sink of a Carnot engine having efficiency are each decreased
by , then the efficiency
remains constant
becomes 1 .
decreases
increases
Efficiency,
.
Comparing with we get, the efficiency increases.
A Carnot engine takes cal. of heat from a reservoir at , and gives it to a sink at .
The work done by the engine is
zero
work Heat
A diatomic ideal gas is used in a car engine as the working substance. If during the adiabatic expansion
part of the cycle, volume of the gas increases from to , the efficiency of the engine is
0.5
0.75
0.99
0.25
The efficiency of cycle is
For adiabatic process
constant
For diatomic gas
A Carnot engine operating between temperatures and has efficiency . When is lowered by
its efficiency increases to . Then and are, respectively
and
On solving Eqs. (i) and (ii)
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