In the diagram, is the initial state and is the final state. The gas goes from I ot by (i) IAF, (ii) IBF, (iii) ICF. The heat absorbed by the gas is
the same in all three processes
the same in (i) and (ii)
greater in (i) than in (ii)
the same in (i) and (iii)
Get Answer
Heat absorbed in a thermodynamic process is given by .
Here is same for all the three processes as it depends only on initial and final states.
But
A closed system undergoes a process for which the values and are and respectively. If the system is returned to state 1 and is the work done is
.
From .
Now .
Heat energy absorbed by a system in going through a cyclic process shown in the given figure is
As , in a cyclic process,
area of circle
or
In a thermodynamic process, pressure of a fixed mass of gas is changed in such a manner that the gas molecules gives out 30 joules of heat and of work is done on the gas. If the initial internal energy of the gas was , then final internal energy will be
zero
Given that and
and let final internal energy
So,
Unit mass of a liquid with volume is completely changed into a gas of volume at a constant external pressure and temperature . If the latent heat of evaporation for the given mass is , then the increase in the internal energy of the system is
Zero
Now
A gas can be taken from to via two different processes and .
When path ACB is used of heat flows into the system and of work is done by the system. If path is used work done by the system is . The heat Flow into the system in path is :
.remains same for both paths and
As change in internal energy depends only on initial and final point
of water at a pressure of is converted into steam without any change of temperature. The volume of of steam is and the latent heat of evaporation is . The change in internal energy due to evaporation of of water is
Joule
,
or .
When the state of a gas adiabatically changed from an equilibrium state to another equilibrium state an amount of work done on the stystem is . If the gas is taken from state A to B via process in which the net heat absorbed by the system is , then the net work done by the system is
In the first-case adiabatic change,
From law of thermodynamics,
In the second case
A sample of an ideal gas is taken through the cyclic process P as shown in figure. It absorbs, of heat during the part , no heat during and rejects of heat during . A work is done on the gas during the part . The internal energy of the gas at is . The work done by the gas during the part is:
In complete cycle
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