4
3
2
1
Get Answer
For the straight line in the graph denoted by 4 , that shows pressure is constant, so curve 4 represents an isobaric process.
For the straight line in graph denoted by 1 , that shows volume is constant, so curve 1 represents isochoric process. Out of curves 3 and 2, curve 2 is steeper. Hence, curve 2 is adiabatic and curve 3 is isothermal.
If an average person jogs, he produces . This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming requires cal for evaporation) is
As we know that amount of sweat evaporated/minute Sweat produced/ minute
Number of calories required for evaporation
Latent heat (in )
calories are needed to convert into stream.
1 cal. will produce sweat
cal will produce (sweat)
.
Consider diagram for an ideal gas shown in figure.
Out of the following diagrams, which figure represents the diagram?
(I)
(II)
(III)
(IV)
`
(iv)
(ii)
(iii)
(i)
According to given diagram that constant
So we can say that the gas is going through an isothermal process.
If pressure increase at constant temperature volume decreases, the graph (iii) shows that pressure is smaller at point 2 and larger at point 1 point so the gas expands and pressure decreases. Hence verifies option (c).
According to the given - diagram.
Work done in the process
Here the direction of arrow is anti-clockwise, so work done is negative.
Hence, work done by the gas
That shows external work done on the system.
Consider two containers and containing identical gases at the same pressure, volume and temperature. The gas in container is compressed to half of its original volume isothermally while the gas in container is compressed to half of its original value adiabatically. The ratio of final pressure of gas in to that of gas in is
Let us consider the diagram for container (isothermal) and for container (adiabatic).
Container
(Isothermal)
In both process compression of the gas.
For isatherma process (gas ) during
For adiabatic process, (gas ) during
So, ratio of final pressure
where, is ratio of specific heat capacities for the gas.
Hence, verifies the option (a).
Three copper blocks of masses and respectively are brought into thermal contact till they reach equilibrium. Before contact, they were at ). Assuming there is no heat loss to the surroundings, the equilibrium temperature is ( is specific heat of copper)
Consider the equilibrium temperature of the system is . Let us consider, .
As given that, there is no net loss to the surroundings.
Heat lost by Heat gained by Heat gained by
(where, is specified heat of the copper material)
General Knowledge
Academics Question Bank
PHYSICS
CHEMISTRY
BIOLOGY
MATHEMATICS
THE WORLD AROUND US
HISTORY
GEOGRAPHY
CIVICS
ECONOMICS
Physics
How - Why - What
NCERT Books (Class 1-12)
Learn At Your Own Pace... Because, Everyone's Pace of Learning is Different...
A unit of Innovexcel Edu Solution LLP.
SWIFT, RELIABLE & CONVENIENT..
Social Media
Corporate Office : Bharat Impact Building, C-26, Sector - 59, Noida, Uttar Pradesh - 201301, India
Excel With Tutors : A Perfect Tutoring Platform & Repository of Learning Materials. Matches the Best Tutor as Per Your Requirement.
© 2025 | ©Innovexcel Edu Solution LLP. All Rights Reserved.
Technology Partner: Indev Consultancy Pvt Ltd