EWT | Academic Question

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Question (31)
QN0036302
A convex lens has focal length 10 cm and an object is placed 30 cm in front of it. The image distance is
  • (A) 10 cm
  • (B) 15 cm
  • (C) 20 cm
  • (D) 30 cm

Correct Answer: B
Explanation:

Using 1/v - 1/u = 1/f with u = -30 cm and f = +10 cm gives v = +15 cm.

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Question (32)
QN0036303
A convex lens has focal length 20 cm and an object is placed 60 cm in front of it. The image distance is
  • (A) 15 cm
  • (B) 20 cm
  • (C) 30 cm
  • (D) 60 cm

Correct Answer: C
Explanation:

Using the lens formula, 1/v = 1/20 - 1/60 = 1/30. Therefore v = +30 cm.

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Question (33)
QN0036304
An object is placed 10 cm from a convex lens of focal length 15 cm. The image formed is
  • (A) real, inverted and diminished
  • (B) real, inverted and enlarged
  • (C) virtual, erect and enlarged
  • (D) virtual, inverted and diminished

Correct Answer: C
Explanation:

The object is inside the focal length, so a convex lens forms a virtual, erect and enlarged image.

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Question (34)
QN0036305
An object of height 5 cm is placed at 2F of a convex lens. The image height is
  • (A) 2.5 cm
  • (B) 5 cm
  • (C) 10 cm
  • (D) 15 cm

Correct Answer: B
Explanation:

An object placed at 2F forms an image of the same size at 2F on the other side of the lens.

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Question (35)
QN0036306
A convex lens forms a real image at 40 cm when the object is placed 20 cm in front of it. The focal length of the lens is approximately
  • (A) 10 cm
  • (B) 13.3 cm
  • (C) 20 cm
  • (D) 30 cm

Correct Answer: B
Explanation:

Using the lens formula, 1/f = 1/40 + 1/20 = 3/40. Hence f = 40/3 ≈ 13.3 cm.

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Question (36)
QN0036307
A convex lens of focal length 20 cm has an object placed 30 cm in front of it. If the object height is 3 cm, the image height is
  • (A) +6 cm
  • (B) -3 cm
  • (C) -6 cm
  • (D) +3 cm

Correct Answer: C
Explanation:

The image distance is 60 cm. Magnification m = v/u = 60/(-30) = -2. Therefore h' = -2 × 3 = -6 cm.

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Question (37)
QN0036308
A concave lens has focal length -20 cm and an object is placed 40 cm in front of it. The image distance is approximately
  • (A) +13.3 cm
  • (B) +20 cm
  • (C) -13.3 cm
  • (D) -40 cm

Correct Answer: C
Explanation:

Using the lens formula with f = -20 cm and u = -40 cm gives v ≈ -13.3 cm.

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Question (38)
QN0036309
For the concave lens in the previous question, the magnification is approximately
  • (A) +0.33
  • (B) -0.33
  • (C) +3
  • (D) -3

Correct Answer: A
Explanation:

m = v/u = (-13.3)/(-40) ≈ +0.33. The positive sign indicates an erect image.

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Question (39)
QN0036310
A concave lens always forms an image that is
  • (A) real, inverted and enlarged
  • (B) real, erect and diminished
  • (C) virtual, erect and diminished
  • (D) virtual, inverted and enlarged

Correct Answer: C
Explanation:

A concave lens forms a virtual, erect and diminished image for a real object.

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Question (40)
QN0036311
A lens produces a magnification of -2 for an object of height 4 cm. The image height is
  • (A) +2 cm
  • (B) -2 cm
  • (C) +8 cm
  • (D) -8 cm

Correct Answer: D
Explanation:

m = h'/h, so h' = m × h = -2 × 4 = -8 cm.

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