Get Answer
Using 1/v - 1/u = 1/f with u = -30 cm and f = +10 cm gives v = +15 cm.
Using the lens formula, 1/v = 1/20 - 1/60 = 1/30. Therefore v = +30 cm.
The object is inside the focal length, so a convex lens forms a virtual, erect and enlarged image.
An object placed at 2F forms an image of the same size at 2F on the other side of the lens.
Using the lens formula, 1/f = 1/40 + 1/20 = 3/40. Hence f = 40/3 ≈ 13.3 cm.
The image distance is 60 cm. Magnification m = v/u = 60/(-30) = -2. Therefore h' = -2 × 3 = -6 cm.
Using the lens formula with f = -20 cm and u = -40 cm gives v ≈ -13.3 cm.
m = v/u = (-13.3)/(-40) ≈ +0.33. The positive sign indicates an erect image.
A concave lens forms a virtual, erect and diminished image for a real object.
m = h'/h, so h' = m × h = -2 × 4 = -8 cm.
General Knowledge
Academics Question Bank
PHYSICS
CHEMISTRY
BIOLOGY
MATHEMATICS
THE WORLD AROUND US
HISTORY
GEOGRAPHY
CIVICS
ECONOMICS
Physics
How - Why - What
NCERT Books (Class 1-12)
Learn At Your Own Pace... Because, Everyone's Pace of Learning is Different...
A unit of Innovexcel Edu Solution LLP.
SWIFT, RELIABLE & CONVENIENT..
Social Media
Corporate Office : Bharat Impact Building, C-26, Sector - 59, Noida, Uttar Pradesh - 201301, India
Excel With Tutors : A Perfect Tutoring Platform & Repository of Learning Materials. Matches the Best Tutor as Per Your Requirement.
© 2025 | ©Innovexcel Edu Solution LLP. All Rights Reserved.
Technology Partner: Indev Consultancy Pvt Ltd