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Question (1)
QN0038813

If a charge  is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through the flat surface would be :                                                                                  

If a charge q is placed at the center of a closed hemispherical non-conducting  surface, - Sarthaks eConnect | Largest Online Education Community

  • (A)

  • (B)

  • (C)

           

  • (D)

    None

Correct Answer: D
Explanation:

(None) Total flux through complete spherical surface is .

So flux, through curved surface will be .

The flux through flat surface will be zero

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Question (2)
QN0038814

Number of electric lines of force that radiate outwards from one coulomb of charge in vacuum is

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

Here,  Number of lines of force  Electric force

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Question (3)
QN0038815

In the figure the net electric flux through the area  is  when the system is in air. On immersing the system in water the net electric flux through the area                                                          

Question No. 174163 SaraNextGen | Toppr Answer

  • (A)

    becomes zero

  • (B)

    remains same

  • (C)

    increases

  • (D)

    decreases 

Correct Answer: D
Explanation:

Since electric field  decreases inside water, therefore flux  also decreases.

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Question (4)
QN0038816

A cylinder of radius  and length  is placed in a uniform electric field  parallel to the axis of the cylinder. The total flux over the curved surface of the cylinder is

  • (A)

    zero

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

For the curved surface,

ds .

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Question (5)
QN0038817

Positive electric flux indicates that electric lines of force are directed

  • (A)

    outwards

  • (B)

    inwards

  • (C)

    either (a) or (b)

  • (D)

    None of these

Correct Answer: A
Explanation:

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Question (6)
QN0038818

Electric flux over a surface in an electric field may be

  • (A)

    positive

  • (B)

    zero

  • (C)

    negative

  • (D)

    All of these

Correct Answer: D
Explanation:

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Question (7)
QN0038819

Consider an electric field  where  is a constant. The flux through the shaded area (as shown in the figure) due to this field is                                                                                                         

Consider an electric field ¯E=E0^x where E0 is a constant. The flux through  the shaded area (as shown in the figure) due to this field is

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

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Question (8)
QN0038820

A surface has the area vector . The flux of an electric field through it if the field is  :

  • (A)

  • (B)

  • (C)

  • (D)

    zero

Correct Answer: A
Explanation:

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Question (9)
QN0038821

The electric field in a region of space is given by,  where . The flux of the field through a circular surface of radius  parallel to the  plane is nearly: 

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

(a)

Given,  So,

Radius of circular surface

Area

[Loop is parallel to Y-Z plane]

Now, flux

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