In a cuboid of dimension , a charge is placed at the centre of the surface 'S' having area of . The flux through the opposite surface to ' ' is given by
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After placing similar cubic at the bottom, we get cube of side having change at its centre.
From the Gauss's law electric flux through whole cube,
Flux passing through shaded face
At the centre of a cubical box charge is placed. The value of total flux that is coming out a wall is
According to Gauss' Law
so total flux
Since cube has six face, so flux coming out through one wall or one face is .
An electric dipole is put in north-south direction in a sphere filled with water. Which statement is correct?
Electric flux is coming towards sphere
Electric flux is coming out of sphere.
Electric flux entering into sphere and leaving the sphere are same.
Water does not permit electric flux to enter into sphere.
If electric dipole, the flux coming out from positive charge is equal to the flux coming in at negative charge i.e. total charge on sphere . From Gauss law, total flux passing through the sphere .
A cylinder of radius and length 1 is placed in an uniform electric field parallel to the axis of the cylinder. The total flux for the surface of the cylinder is given by-
zero
Since-ve electric flux ve flux electric flux enclosed with a cylinder here
Total Electric
Flux .
A charge is enclosed by a Gaussian spherical surface of radius . If the radius is doubled, then the outward electric flux will
increase four times
remain the same
be reduced to half
be doubled
By.Gauss's theorem,
Thus, the net flux depends only on the charge enclosed by the surface. Hence, there will be no effect on the net flux if the radius of the surface is doubled.
A charge is at a distance above a square of side . Then what is the flux linked with the surface?
A point charge is positioned at the center of the base of a square pyramid as shown. The flux through one of the four identical upper faces of the pyramid is
None of these
Flux going in pyramid .
which is divided equally among all 4 faces.
Flux through one face
Electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius surrounding the total charge is . The flux over the concentric sphere of radius will be
Flux does not depend on the size and shape of the close surface, and so, it remains same.
A loop of diameter is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be . What is the electric field strength?
.
A hollow cylinder has a charge coulomb within it. If is the electric flux in units of voltmeter associated with the curved surface , the flux linked with the plane surface in units of voltmeter will be
Since ,
where is the total charge.
As shown in the figure, flux associated with the curved surface is
Let us assume flux linked with the plane surfaces and be
Therefore,
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