EWT | Academic Question

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Question (1)
QN0038969

A capacitor of  is connected as shown in the circuit. The internal resistance of the battery is . The amount of charge on the capacitor plates will be                                                                                                   

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: D
Explanation:

As capacitor offers infinite resistance in dc-circuit. So, current flows through  resistance from left to right, given by

So, the potential difference across  resistance

Since, capacitor is in parallel with  resistance, so it also has  potential difference across it.

As current does not flow through capacitor branch so no potential drop will be accross  resistance. The charge on capacitor

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Question (2)
QN0038970

A positively charged particle is released from rest in an uniform electric field. The electric potential energy of the charge  

  • (A)

    remains a constant because the electric field is uniform

  • (B)

    increases because the charge moves along the electric field

  • (C)

    decreases because the charge moves along the electric field

  • (D)

    decreases because the charge moves opposite to the electric field

Correct Answer: C
Explanation:

The direction of electric field is always perpendicular to the direction of electric field and equipotential surface maintained at high electrostatic potential to other equipotential surface maintained at low electrostatic potential.

The positively charged particle experiences the electrostatic force in the direction of electric field i.e., from high electrostatic potential to low electrostatic potential. Thus, the work done by the electric field on the positive charge, so electrostatic potential energy of the positive charge decreases because speed of charged particle moves in the direction of field due to force .

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Question (3)
QN0038971

Figure shows some equipotential lines distributed in space. A charged object is moved from point  to point .

  • (A)

    The work done in Fig. (i) is the greatest

  • (B)

    The work done in Fig. (ii) is least

  • (C)

    The work done is the same in Fig. (i), Fig.(ii) and Fig. (iii)

  • (D)

    The work done in Fig. (iii) is greater than Fig. (ii) but equal to that in

Correct Answer: C
Explanation:

The work done (in displacing a charge particle) by a electric force is given by . Here initial and final potentials are same in all three cases are equal (20V) and same charge is moving from A to B, so work done is  same in all three cases.

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Question (4)
QN0038972

The electrostatic potential on the surface of a charged conducting sphere is . Two statements are made in this regard  at any point inside the sphere, electric intensity is zero.  at any point inside the sphere, the electrostatic potential is . Which of the following is a correct statement?              

  • (A)

    is true but  is false

  • (B)

    Both  and  are false

  • (C)

    is true,  is also true and  is the cause of 

  • (D)

    is true,  is also true but the statements are independant

Correct Answer: C
Explanation:

As we know that the relation between electric field intensity  and electric potential  is

Electric field intensity  then

This imply that  constant

Thus,  inside the charged conducting sphere then the constant electrostatic potential  at every where inside the sphere and it verifies the shielding effect also.

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Question (5)
QN0038973

Equipotentials at a great distance from a collection of charges whose total sum is not zero are approximately

  • (A)

    spheres

  • (B)

    planes

  • (C)

    paraboloids

  • (D)

    ellipsoids

Correct Answer: A
Explanation:

Here we have to findout the shape of equipotential surface, these surface are perpendicular to the field lines; so there must be electric field which can not be without charge.

So, the collection of charges, whose total sum is not zero, with regard to great distance can be considered as a point charge. The equipotentials due to point charge are spherical in shape as electric potential due to point charge  is given by

This suggest that electric potentials due to point charge is same for all equidistant points. The locus of these equidistant points which are at same potential, form spherical surface.

The lines of field from point charge are radial. So the equipotential surface perpendicular to field lines from a sphere.

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Question (6)
QN0038974

A parallel plate capacitor is made of two dielectric blocks in series. One of the blocks has thickness  and dielectric constant  and the other has thickness  and dielectric constant  as shown in figure. This arrangement can be thought as a dielectric slab of thickness  and effective dielectric constant . The is

                                                                                                                

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

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