A dipole is placed in an electric field as shown. In which direction will it move?
Towards the right as its potential energy will increase.
Towards the left as its potential energy will increase.
Towards the right as its potential energy will decrease.
Towards the left as its potential energy will decrease.
Get Answer
Potential energy of electric dipole in external electric field
Since angle between and is
On moving towards right electric field strength decrease
decreases.
Net force on electric dipole is towards right and net torque acting on it is zero so move towards right.
Note : Potential energy of a dipole stable equilibrium and i.e., minimum value. For and dipole is not in equilibrium. For i.e., maximum value and dipole is in unstable equilibrium.
The equivalent capacitance of the combination shown in the figure is
The circuit is as shown is figure,
Points are connected by conducting wire so these points are at same potential.
So the capacitor is short circuited. So it does not store any charge.
Therefore equivalent capacitance
Twenty seven drops of same size are charged at each. They combine to form a bigger drop. Calculate the potential of the bigger drop.
Let charge and radius of smaller drop is and respectively and radius of bigger drop
For smaller drop, electric potential,
As volume remains the same
And from conservation of charge,
Potential of bigger drop,
Two hollow conducting spheres of radii and ) have equal charges.
The potential would be :
more on smaller sphere
equal on both the spheres
dependent on the material property of the sphere
more on bigger sphere
Potential, of hollow conducting sphere,
constant
So,
The angle between the electric lines of force and the equipotential surface is:
Electric field vectors are always to equipotential surface.
A capacitor of capacitance is charged fully by 100 battery as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance as shown in figure (b). The electrostatic energy stored by the system (b) is
By conservation of charge
An electric dipole is placed as shown in the figure.
The electric potential (in ) at point due to the dipole is ( permittivity of free space and )
Electrostatic potential due to a point charge is given by
Six charges and are fixed at the corners of a hexagon of side as shown in the figure. The work done in bringing a charge to the centre of the hexagon from infinity is :
( - permittivity of free space)
Zero
Potential at the centre of hexagon is zero i.e.,
The equivalent capacitance of the system shown in the following circuit is
For parallel grouping,
For series grouping,
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