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The difference between consecutive terms in option (b) is always 4. Hence, it is an AP.
d = 12 - 17 = -5.
If d = 0, all terms are equal, so the AP is constant.
The terms of an AP are a, a + d, a + 2d, a + 3d, ...
a8 = a + 7d. Thus, 31 = a + 28, giving a = 3.
a20 = 7 + 19(5) = 102.
a15 = 14 + 14(-4) = -42.
64 = 7 + 19d, so 19d = 57 and d = 3.
79 = 4 + (n - 1)5. Hence, n - 1 = 15 and n = 16.
2 = 50 - 4(n - 1). Thus, n - 1 = 12 and n = 13.
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