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a11 - a5 = 6d. Therefore, 42 - 18 = 6d, giving d = 4.
6d = 29 - 11 = 18, so d = 3. Therefore, a + 9 = 11, giving a = 2.
5d = 32 - 12 = 20, so d = 4. Then a = 4 and a15 = 4 + 14(4) = 60.
51 = 6 + 5(n - 1), giving n = 10. Hence 51 is a term.
The general term is 5 + 4(n - 1), so every term is congruent to 1 modulo 4. Since 60 does not satisfy the equation, it is not a term.
103 = 8 + 5(n - 1). Thus, n - 1 = 19 and n = 20.
156 = 11 + 5(n - 1). Therefore, n - 1 = 29 and n = 30.
The sequence is 10, 15, ..., 95. Number of terms = (95 - 10)/5 + 1 = 18.
The sequence is 108, 117, ..., 999. Number of terms = (999 - 108)/9 + 1 = 100.
The kth term from the end is the (n - k + 1)th term from the beginning. Thus, 30 - 12 + 1 = 19.
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