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a7 = 700. Hence, S7 = 7/2(550 + 700) = 4375.
The seven prizes form an AP. The middle term equals the average prize value: 700/7 = Rs.100.
One section plants 1 + 2 + ... + 12 = 78 trees. Three sections plant 3(78) = 234 trees.
The last penalty is 200 + 29(50) = Rs.1650. Total = 30/2(200 + 1650) = Rs.27750.
Sum of radii = 13/2(0.5 + 6.5) = 45.5. Semicircle length = pi r, so total = 22/7 x 45.5 = 143 m.
For n rows, 200 = n/2
The distances form an AP with 10 terms. Sum = 10/2(5 + 32) = 185 m. Round-trip distance = 2(185) = 370 m.
5 = 23 + (n - 1)(-2). Thus, 18 = 2(n - 1), giving n = 10.
an = Sn - S(n-1). Therefore, an = 3n² + 2n -
For three numbers in AP, the middle term is the arithmetic mean of the first and third terms. Hence, b = (a + c)/2.
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