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The polynomial is (x - 5)(x + 2) = x² - 3x - 10.
Sum = 7/2 and product = 3/2. Hence polynomial = 2x² - 7x + 3.
Polynomial = x² - (sum)x + product = x² - 6x + 8.
Product of zeroes = (-4)(-1) = 4 = c/3. Therefore, c = 12.
1/α + 1/β = (α + β)/(αβ) = (13/5)/(6/5) = 13/6.
α + β = 6 and αβ = 5. Therefore, α² + β² = (α + β)² - 2αβ = 36 - 10 = 26.
α²β + αβ² = αβ(α + β) = 1 × 5/2 = 5/2.
(α - β)² = (α + β)² - 4αβ. Thus 4 = 64 - 4k, giving k = 15.
Let the zeroes be t and 2t. Then 3t = 6, so t = 2. Therefore, k = t(2t) = 4.
Equal zeroes imply the discriminant condition p² - 4q = 0. Hence p² = 4q.
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