EWT | Academic Question

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Question (31)
QN0036651
The roots of x²−11x+30=0 are:
  • (A) 4 and 7
  • (B) 5 and 6
  • (C) 3 and 10
  • (D) 2 and 15

Correct Answer: B
Explanation:

x²−11x+30=(x−5)(x−6). Hence the roots are 5 and 6.

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Question (32)
QN0036652
If one root of 2x²−9x+10=0 is 2, the other root is:
  • (A) 2
  • (B) 5/2
  • (C) 3
  • (D) 4

Correct Answer: B
Explanation:

2x²−9x+10=(2x−5)(x−2). Hence the other root is 5/2.

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Question (33)
QN0036653
The roots of 6x²−x−2=0 are:
  • (A) 2/3, −1/2
  • (B) 3/2, −1/2
  • (C) 2/3, 1/2
  • (D) −2/3, 1/2

Correct Answer: A
Explanation:

6x²−x−2=(3x−2)(2x+1). Hence x=2/3 and −1/2.

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Question (34)
QN0036654
The equation x²−10x+25=0 can be written as:
  • (A) (x+5)²=0
  • (B) (x−5)²=0
  • (C) (x−25)(x−1)=0
  • (D) (x−10)(x+25)=0

Correct Answer: B
Explanation:

x²−10x+25=(x−5)².

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Question (35)
QN0036655
For which value of k will x²−2(k+1)x+k²=0 have equal roots?
  • (A) 1/2
  • (B) 1
  • (C) −1/2
  • (D) 2

Correct Answer: C
Explanation:

Equal roots require 4(k+1)²−4k²=0. Thus 2k+1=0, so k=−1/2.

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Question (36)
QN0036656
If x=3 is a root of 2x²+kx−15=0, then k equals:
  • (A) −1
  • (B) 1
  • (C) 3
  • (D) 5

Correct Answer: A
Explanation:

2(3)²+3k−15=0 gives 18+3k−15=0, so k=−1.

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Question (37)
QN0036657
For what value of k does x²+4x+k=0 have no real roots?
  • (A) k<4
  • (B) k=4
  • (C) k>4
  • (D) k=0

Correct Answer: C
Explanation:

D=16−4k. For no real roots, 16−4k<0, so k>4.

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Question (38)
QN0036658
If x²−6x+k=0 has two distinct real roots, then:
  • (A) k>9
  • (B) k=9
  • (C) k<9
  • (D) k=0 only

Correct Answer: C
Explanation:

D=36−4k>0, hence k<9.

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Question (39)
QN0036659
If x²+px+9=0 has equal roots, then p can be:
  • (A) 3 only
  • (B) −3 only
  • (C) ±6
  • (D) ±3

Correct Answer: C
Explanation:

For equal roots, p²−36=0. Therefore p=±6.

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Question (40)
QN0036660
The equation 4x²+4x+1=0 has roots:
  • (A) 1,1
  • (B) −1,−1
  • (C) 1/2,1/2
  • (D) −1/2,−1/2

Correct Answer: D
Explanation:

4x²+4x+1=(2x+1)². Hence x=−1/2 is the repeated root.

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