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D=2²−4(5)(−3)=4+60=64.
D=4²−4(4)(3)=16−48=−32<0. Hence there are no real roots.
If the distances are x and x+7, Pythagoras gives x²+(x+7)²=13², which simplifies to x²+7x−60=0.
x²+7x−60=(x+12)(x−5). The roots are −12 and 5. Since distance is positive, x=5.
The positive root is x=5. The other distance is x+7=12 m.
For real roots, the discriminant b²−4ac must be non-negative.
Equal roots require 64−4k=0, so k=16.
Sum of roots=10 and product=21. Therefore the equation is x²−10x+21=0.
Product of roots=12. If one root is 4, the other root=12/4=3.
Let breadth=x and length=2x. Then 2x²=800, giving x=20 m and length=40 m.
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