EWT | Academic Question

Questions
Question (41)
QN0037061
41. For the tent in Question 40, if canvas costs ₹500 per m², the approximate cost is:
  • (A) ₹18,000
  • (B) ₹20,000
  • (C) ₹22,000
  • (D) ₹25,000

Correct Answer: C
Explanation:

Canvas area = 44 m². Cost = 44 × 500 = ₹22,000.

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Question (42)
QN0037062
42. A cylindrical vessel has radius 5 cm and height 8 cm. A hemispherical cavity of radius 5 cm is cut from one end. The volume removed by the cavity is:
  • (A) 125π/3 cm³
  • (B) 250π/3 cm³
  • (C) 500π/3 cm³
  • (D) 750π/3 cm³

Correct Answer: B
Explanation:

Volume of hemisphere = 2/3πr³ = 2/3π × 125 = 250π/3 cm³.

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Question (43)
QN0037063
43. A cone-shaped vessel has height 8 cm and radius 5 cm. Its capacity is:
  • (A) 100π/3 cm³
  • (B) 150π/3 cm³
  • (C) 200π/3 cm³
  • (D) 250π/3 cm³

Correct Answer: C
Explanation:

Volume = 1/3πr²h = 1/3π × 25 × 8 = 200π/3 cm³.

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Question (44)
QN0037064
44. Lead shots of radius 0.5 cm are dropped into a completely filled vessel. If one-fourth of the water flows out, the volume of displaced water is equal to:
  • (A) Volume of one lead shot
  • (B) Total volume of all lead shots
  • (C) Half the volume of all lead shots
  • (D) Twice the volume of all lead shots

Correct Answer: B
Explanation:

The volume of water displaced equals the volume occupied by the submerged lead shots.

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Question (45)
QN0037065
45. A spherical glass vessel has a cylindrical neck. To calculate its capacity, which volumes should be combined?
  • (A) Only the spherical part
  • (B) Only the cylindrical neck
  • (C) Volume of spherical part and cylindrical neck
  • (D) Difference between spherical and cylindrical volumes

Correct Answer: C
Explanation:

The vessel consists of a spherical portion and a cylindrical neck, so their volumes are added.

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Question (46)
QN0037066
46. A solid iron pole consists of a cylinder of height 220 cm and diameter 24 cm, surmounted by a cylinder of height 60 cm and radius 8 cm. The radius of the lower cylinder is:
  • (A) 6 cm
  • (B) 8 cm
  • (C) 12 cm
  • (D) 24 cm

Correct Answer: C
Explanation:

Radius = diameter/2 = 24/2 = 12 cm.

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Question (47)
QN0037067
47. For the iron pole in Question 46, using π = 3.14, the volume of the lower cylinder is:
  • (A) 99440 cm³
  • (B) 99475.2 cm³
  • (C) 100000 cm³
  • (D) 101376 cm³

Correct Answer: B
Explanation:

Volume = πr²h = 3.14 × 12² × 220 = 99475.2 cm³.

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Question (48)
QN0037068
48. A solid consisting of a cone of radius 60 cm and height 120 cm standing on a hemisphere of radius 60 cm is placed in a cylinder of radius 60 cm and height 180 cm. The volume of water left is:
  • (A) 678240 cm³
  • (B) 813888 cm³
  • (C) 1017360 cm³
  • (D) 1220832 cm³

Correct Answer: B
Explanation:

Cylinder volume = π × 60² × 180. Solid volume = cone volume + hemisphere volume. Subtracting the solid volume from the cylinder volume gives approximately 813888 cm³ using π = 22/7.

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Question (49)
QN0037069
49. A pen stand is a cuboid of dimensions 15 cm × 10 cm × 3.5 cm with four conical depressions. Each depression has radius 0.5 cm and depth 1.4 cm. The volume of wood removed from the four depressions is:
  • (A) 1.47 cm³
  • (B) 1.67 cm³
  • (C) 2.47 cm³
  • (D) 3.14 cm³

Correct Answer: A
Explanation:

One depression volume = 1/3 × 22/7 × 0.5² × 1.4 ≈ 0.3667 cm³. Four depressions ≈ 1.47 cm³.

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Question (50)
QN0037070
50. A solid is formed by joining a cone and a hemisphere of the same radius. Which statement correctly describes the calculation of its volume and external surface area?
  • (A) Both are obtained by simply adding the TSA of the two solids
  • (B) Volume is the sum of constituent volumes, while the common joining surface is excluded from external surface area
  • (C) Volume is the difference of constituent volumes, while all surfaces are included
  • (D) Both volume and surface area are calculated by adding only the curved surfaces

Correct Answer: B
Explanation:

When solids are joined, their volumes are added, but the common joining surface is internal and is not counted in the external surface area.

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