EWT | Academic Question

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Question (21)
QN0035655

Which of the following expressions represents the excess of pressure inside the soap bubble?

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: D
Explanation:

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Question (22)
QN0035656

A drop of liquid pf density  is floating half immersed in a liquid of density  and surface tension . The radius of drop in  will be : (Take :  )

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

As liquid drop is in equilibrium.

So

Boyant force + surface tension

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Question (23)
QN0035657

The work done in increasing the size of a soap film from  to  is . The surface tension of the film is

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

Work done,  (Change in area)

there are two free surface

Surface tension,

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Question (24)
QN0035658

A mercury drop of radius  is sprayed into  drops of equal size. The energy expressed in joule is (surface tension of Mercury is  ) 

  • (A)

    0.057

  • (B)

    5.7

  • (C)

  • (D)

Correct Answer: A
Explanation:

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Question (25)
QN0035659

Work done in increasing the size of a soap bubble from radius  to  is nearly (surface tension of soap solution  )

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: C
Explanation:

Work done  Change in surface energy

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Question (26)
QN0035660

Two small drops of mercury each of radius  coalesce to form a single large drop. The ratio of total surface energy before and after the change is :         

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

As volume remain same i.e volume of two smaller drops will be equal to volume of one big drop.

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Question (27)
QN0035661

An isolated and charged spherical soap bubble has a radius  and the pressure inside is atmospheric. If  is the surface tension of soap solution, then charge on drop is  then find the value of .

  • (A)

    8

  • (B)

    +9

  • (C)

    7

  • (D)

    2

Correct Answer: A
Explanation:

Inside pressure must be  greater than outside pressure in bubble.

This excess pressure is provided by charge on bubble.

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Question (28)
QN0035662

A glass tube of uniform internal radius  has a valve separating the two identical ends. Initially, the valve is in a tightly closed position. End 1 has a hemispherical soap bubble of radius . End 2 has sub-hemispherical soap bubble as shown in figure. Just after opening the valve      

  • (A)

    air from end 1 flows towards end 2. No change in the volume of the soap bubbles

  • (B)

    air from end 1 flows towards end 2. Volume of the soap bubble at end 1 decreases

  • (C)

    no change occurs

  • (D)

    air from end 2 flows towards end 1. Volume of the soap bubble at end 1 increases

Correct Answer: B
Explanation:

Pressure inside tube

(since  )

Hence pressure on side 1 will be greater than side 2. So air from end 1 flows towards end 2

Subhemispherical                                Hemispherical

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Question (29)
QN0035663

The lower end of a capillary tube of radius  is placed vertically in water. Then, with the rise of water in the capilllary, heat evolved is:

  • (A)

  • (B)

  • (C)

  • (D)

Correct Answer: A
Explanation:

radius radius 

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Question (30)
QN0035664

A glass capillary tube of inner diameter  is lowered vertically into water in a vessel. The pressure to be applied on the water in the tube so that water level in the tube is same as that in the vessel in  is (surface tension of water , atmospheric pressure  )  

  • (A)

  • (B)

            

  • (C)

     

  • (D)

Correct Answer: B
Explanation:

Pressure applied,

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