A body is thrown vertically upwards. If air resistance is to be taken into account, then the time during which the body rises is
equal to the time of fall
less than the time of fall
greater than the time of fall
twice the time of fall
Get Answer
Let the initial velocity of ball be . Time of rise and height reached
Time of fall is given by
because
A body is thrown upwards and reaches half of its maximum height. At that position
its acceleration is minimum
its velocity is maximum
its velocity is zero
its acceleration is constant
Because acceleration due to gravity is constant so the slope of line will be constant i.e. velocity time curve for a body projected vertically upwards is straight line.
Velocity-time curve for a body projected vertically upwards is
parabola
ellipse
hyperbola
straight line
An object accelerated downward under the influence of force of gravity. The motion of object is said to be
uniform motion
free fall
non uniformly accelerated motion
None of these
Free fall of an object (in vacuum) is a case of motion with
uniform velocity
uniform acceleration
variable acceleration
constant momentum
Free fall of an object (in vacuum) is a case of motion with uniform acceleration.
A ball thrown vertically upwards after reaching a maximum height , returns to the starting point after a time of . Its displacement is
zero
As ball returns to starting point so displacement is zero.
A ball is released from a height . If and be the time required to complete first half and second half of the distance respectively. Then, choose the correct relation between and .
The equation represented by the graph below is :
A body is projected vertically upwards. If and be the times at which it is at height above the projection while ascending and descending respectively, then is
.
Also
After simplify above equations, we get .
From a tower of height , a particle is thrown vertically upwards with a speed of . If the time taken by if to reach the highest point is then the time taken by the particle to hit the ground is
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