A body released from the top of a tower falls through half the height of the tower in . In what time shall the body fall through the height of the tower?
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For constant acceleration and zero initial velocity
Two bodies of masses and fall from heights and respectively. The ratio of their velocities, when they hit the ground is
When a body fallsthrough a height , it acquires a velocity .
A stone falls from a balloon that is descending at a uniform rate of . The displacement of the stone from the point of release after is
Displacement
A body thrown vertically so as to reach its maximum height in second. Total time from the time of projection to reach a point at half of its maximum height while returning (in ) is
The ratio of distances traversed in successive intervals of time when a body falls freely under gravity from certain height is
As we know, distance traversed in second
Here,
Distance traversed in second i.e.,
A body dropped from top of a tower fall through during the last two seconds of its fall. The height of tower is
Let the body fall through the height of tower in seconds. From, we have, total distance travelled in last 2 second of fall is
Distance travelled in second is
A stone thrown upward with a speed from the top of the tower reaches the ground with a velocity . The height of the tower is
The stone rises up till its vertical velocity is zero and again reached the top of the tower with a speed (downward). The speed of the stone at the base is .
Hence or (a) From third equation of mation
In first case initial velocity
final velocity
and max. height obtained is , then,
In second case
and max. height is then, .
It implies that
A stone thrown vertically upwards with a speed of attains a height . Another stone thrown upwards from the same point with a speed of attains a height . The correct relation between and is
From a pole of height , a stone is thrown vertically upwards with a speed . The time taken by the stone, to hit the ground, is times that taken by it to reach the highest point of its path. The value of is
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