EWT | Academic Question

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Question (31)
QN0036402
Two resistors of 6 Ω and 3 Ω are connected in parallel. Their equivalent resistance is:
  • (A) 2 Ω
  • (B) 3 Ω
  • (C) 6 Ω
  • (D) 9 Ω

Correct Answer: A
Explanation:

1/R = 1/6 + 1/3 = 1/2, so R = 2 Ω.

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Question (32)
QN0036403
Three resistors of 6 Ω each are connected in parallel. Their equivalent resistance is:
  • (A) 18 Ω
  • (B) 9 Ω
  • (C) 3 Ω
  • (D) 2 Ω

Correct Answer: D
Explanation:

For three equal resistors in parallel, R = 6/3 = 2 Ω.

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Question (33)
QN0036404
A 12 V battery is connected across a 4 Ω resistor. The current through the resistor is:
  • (A) 0.33 A
  • (B) 2 A
  • (C) 3 A
  • (D) 48 A

Correct Answer: C
Explanation:

I = V/R = 12/4 = 3 A.

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Question (34)
QN0036405
Two resistors of 10 Ω and 20 Ω are connected in parallel across 10 V. The total current supplied by the battery is:
  • (A) 0.5 A
  • (B) 1.0 A
  • (C) 1.5 A
  • (D) 2.0 A

Correct Answer: C
Explanation:

Branch currents are 1 A and 0.5 A. Total current = 1.5 A.

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Question (35)
QN0036406
In a parallel combination, the potential difference across each resistor is:
  • (A) Different for every resistor
  • (B) Zero
  • (C) The same
  • (D) Always half the battery voltage

Correct Answer: C
Explanation:

Each parallel branch is connected across the same two points, so the potential difference is the same.

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Question (36)
QN0036407
A 6 Ω and a 3 Ω resistor are connected in parallel to a 12 V source. The current through the 6 Ω resistor is:
  • (A) 1 A
  • (B) 2 A
  • (C) 3 A
  • (D) 6 A

Correct Answer: B
Explanation:

I = V/R = 12/6 = 2 A.

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Question (37)
QN0036408
A 6 Ω and 3 Ω resistor are connected in parallel across 12 V. The total current is:
  • (A) 2 A
  • (B) 4 A
  • (C) 6 A
  • (D) 8 A

Correct Answer: C
Explanation:

Currents are 2 A and 4 A. Total current = 6 A.

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Question (38)
QN0036409
A 4 Ω resistor and a 12 Ω resistor are connected in series across 32 V. The potential difference across the 12 Ω resistor is:
  • (A) 8 V
  • (B) 16 V
  • (C) 24 V
  • (D) 32 V

Correct Answer: C
Explanation:

Total R = 16 Ω, I = 2 A. Voltage across 12 Ω = 2 × 12 = 24 V.

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Question (39)
QN0036410
A 20 Ω lamp and a 4 Ω resistor are connected in series to a 6 V battery. The current through the circuit is:
  • (A) 0.10 A
  • (B) 0.20 A
  • (C) 0.25 A
  • (D) 1.50 A

Correct Answer: C
Explanation:

Total resistance = 24 Ω. I = 6/24 = 0.25 A.

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Question (40)
QN0036411
In Question 39, the potential difference across the 20 Ω lamp is:
  • (A) 1 V
  • (B) 2 V
  • (C) 5 V
  • (D) 6 V

Correct Answer: C
Explanation:

V = IR = 0.25 × 20 = 5 V.

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