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H = I²Rt = 3² × 2 × 10 = 180 J.
H = I²Rt, so doubling current makes heat four times.
H = I²Rt = 2² × 5 × 20 = 400 J.
P = VI = 220 × 2 = 440 W.
Energy = 0.1 kW × 5 h = 0.5 kWh.
P = I²R = 5² × 44 = 1100 W.
I = P/V = 100/220 ≈ 0.45 A.
Energy = 0.4 × 8 × 30 = 96 kWh.
Energy = P × t = 1 × 3 = 3 kWh.
First appliance uses 250 Wh. Second uses 1200 × 10/60 = 200 Wh. Therefore, the 250 W appliance consumes more energy.
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