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Question (21)

QN0036342

In a myopic eye, the image of a distant object is formed:

(A) Behind the retina
(B) On the retina
(C) In front of the retina
(D) On the cornea

Correct Answer: C

Explanation:

In myopia, the image of a distant object is formed in front of the retina.

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Question (22)

QN0036343

In a hypermetropic eye, light from a nearby object tends to form an image:

(A) In front of the retina
(B) Behind the retina
(C) On the retina
(D) On the iris

Correct Answer: B

Explanation:

In hypermetropia, the image of a nearby object tends to form behind the retina.

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Question (23)

QN0036344

A myopic person's far point is 80 cm. The corrective lens should have approximately what focal length?

(A) +0.80 m
(B) −0.80 m
(C) +1.25 m
(D) −1.25 m

Correct Answer: B

Explanation:

For a distant object, the corrective concave lens forms a virtual image at 0.80 m, so f = −0.80 m.

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Question (24)

QN0036345

A myopic person has a far point of 80 cm. What is the approximate power of the corrective lens?

(A) +1.25 D
(B) −1.25 D
(C) +0.80 D
(D) −0.80 D

Correct Answer: B

Explanation:

P = 1/f = 1/(−0.80) = −1.25 D.

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Question (25)

QN0036346

A lens of power −5.5 D is used to correct distant vision. Its focal length is approximately:

(A) −0.18 m
(B) +0.18 m
(C) −5.5 m
(D) +5.5 m

Correct Answer: A

Explanation:

f = 1/P = 1/(−5.5) ≈ −0.18 m.

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Question (26)

QN0036347

A person requires a lens of power +1.5 D for near vision. The focal length of this lens is approximately:

(A) −0.67 m
(B) +0.67 m
(C) +1.5 m
(D) −1.5 m

Correct Answer: B

Explanation:

f = 1/P = 1/1.5 ≈ +0.67 m.

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Question (27)

QN0036348

A hypermetropic person's near point is 1 m. To read an object placed at 25 cm, the corrective lens should form the image of the object at:

(A) 25 cm behind the lens
(B) 1 m on the same side as the object
(C) Infinity
(D) 1 m on the opposite side of the lens

Correct Answer: B

Explanation:

The convex lens should form a virtual image at the person's near point of 1 m on the same side as the object.

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Question (28)

QN0036349

For the hypermetropic eye with near point 1 m, the approximate power of the corrective lens required to read at 25 cm is:

(A) +1 D
(B) +2 D
(C) +3 D
(D) −3 D

Correct Answer: C

Explanation:

1/f = 1/(−1) − 1/(−0.25) = −1 + 4 = 3, so P = +3 D.

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Question (29)

QN0036350

A student with a myopic eye has a far point of 1.2 m. Which lens should be used to restore distant vision?

(A) Convex lens
(B) Concave lens
(C) Plane mirror
(D) Prism

Correct Answer: B

Explanation:

A concave lens corrects myopia by bringing the image of a distant object onto the retina.

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Question (30)

QN0036351

If the far point of a myopic person is 1.2 m, the approximate power of the corrective lens is:

(A) +0.83 D
(B) −0.83 D
(C) +1.2 D
(D) −1.2 D

Correct Answer: B

Explanation:

f = −1.2 m, so P = 1/f = −0.83 D approximately.

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Question (21)

In a myopic eye, the image of a distant object is formed:

Explanation:

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Question (22)

In a hypermetropic eye, light from a nearby object tends to form an image:

Explanation:

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Question (23)

A myopic person's far point is 80 cm. The corrective lens should have approximately what focal length?

Explanation:

Link:

Question (24)

A myopic person has a far point of 80 cm. What is the approximate power of the corrective lens?

Explanation:

Link:

Question (25)

A lens of power −5.5 D is used to correct distant vision. Its focal length is approximately:

Explanation:

Link:

Question (26)

A person requires a lens of power +1.5 D for near vision. The focal length of this lens is approximately:

Explanation:

Link:

Question (27)

A hypermetropic person's near point is 1 m. To read an object placed at 25 cm, the corrective lens should form the image of the object at:

Explanation:

Link:

Question (28)

For the hypermetropic eye with near point 1 m, the approximate power of the corrective lens required to read at 25 cm is:

Explanation:

Link:

Question (29)

A student with a myopic eye has a far point of 1.2 m. Which lens should be used to restore distant vision?

Explanation:

Link:

Question (30)

If the far point of a myopic person is 1.2 m, the approximate power of the corrective lens is:

Explanation:

Link:

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