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Fe + CuSO₄ → FeSO₄ + Cu. Iron displaces copper from copper sulphate, causing copper to deposit and the blue colour to fade.
Iron replaces or displaces copper from copper sulphate.
The reaction has a 1:1 ratio between Fe and Cu displaced. Therefore, 3 Fe atoms can displace 3 Cu atoms.
Zinc displaces copper from copper sulphate, forming zinc sulphate and copper.
The reaction ratio of Pb to Cu is 1:1. Therefore, 2 Pb atoms produce 2 Cu atoms.
Na₂SO₄ + BaCl₂ → BaSO₄ + 2NaCl. BaSO₄ is insoluble in water and forms the white precipitate.
The balanced equation contains a coefficient of 2 before NaCl, so two NaCl units are formed per BaSO₄ unit.
Exchange of ions makes it a double displacement reaction, while formation of an insoluble salt makes it a precipitation reaction.
Na₂SO₄ + BaCl₂ → BaSO₄ + 2NaCl.
Copper gains oxygen on heating: 2Cu + O₂ → 2CuO. Copper oxide is black.
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