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Sine and cosine are equal at 45°.
A and B are complementary angles, so sin A = cos B.
The two acute angles of a right triangle add up to 90°. Therefore, the other angle is 90° − 35° = 55°.
sin A = opposite/hypotenuse = 7/25.
tan A = opposite/adjacent = 9/12 = 3/4.
By Pythagoras, the other leg is 12 cm. Hence cos A = 12/13.
A = 30°. Thus sin A + cos A = 1/2 + √3/2 = (√3 + 1)/2.
A = 60°. Hence sin A cos A = (√3/2)(1/2) = √3/4.
(1 − 3/5)/(1 + 3/5) = (2/5)/(8/5) = 1/4.
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