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(1 − 9/16)/(1 + 9/16) = (7/16)/(25/16) = 7/25.
Adjacent:opposite = 4:3, giving a 3-4-5 triangle. Hence sin A = 3/5.
Using sec²A = 1 + tan²A, sec²A − tan²A = 1.
Using cosec²A = 1 + cot²A, the difference is 1.
sin A/cos A = tan A = 2/3 and cos A/sin A = cot A = 3/2. Therefore, the sum is 2/3 + 3/2 = 13/6.
tan A/sec A = (sin A/cos A)/(1/cos A) = sin A = 12/13.
Since B = 90° − A, tan B = cot A = 4/3.
sin A = √3/2 gives A = 60°. Therefore, B = 90° − 60° = 30°.
From the identity sec²A = 1 + tan²A, we get sec²A − tan²A = 1.
Since sin²A + cos²A = 1, the expression is 1 + tan²A = 1 + 9/16 = 25/16.
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