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x = y + 1. Therefore, 3(y + 1) + 2y = 13, giving y = 2 and x = 3. Hence x + y = 5.
The second equation is twice the first, so the lines coincide.
5/10 = 2/4, but 9/15 ≠ 1/2. Hence the lines are parallel.
Coincident lines have infinitely many common points and form a dependent pair.
In substitution, one variable is expressed in terms of the other and substituted into the second equation.
Adding gives 2x = 12, so x = 6 and y = 3. Therefore, xy = 18.
The second equation is twice the first, so infinitely many solutions exist.
x = 5 - y. Substitution gives 2(5 - y) + 5y = 19, so y = 3.
7/14 = (-3)/(-6) = 1/2, but 8/20 ≠ 1/2. Hence the lines are parallel.
Substituting x = 2 and y = 3 gives 2a + 3 = 7, so a = 2.
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