EWT | Academic Question

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Question (31)
QN0036601
A taxi charges a fixed amount plus a charge per kilometre. If 10 km costs ₹105 and 15 km costs ₹155, the charge per kilometre is:
  • (A) ₹8
  • (B) ₹10
  • (C) ₹12
  • (D) ₹15

Correct Answer: B
Explanation:

The additional ₹50 is for 5 km. Therefore, charge per kilometre = 50/5 = ₹10.

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Question (32)
QN0036602
Using the taxi data in the previous question, the fixed taxi charge is:
  • (A) ₹5
  • (B) ₹10
  • (C) ₹15
  • (D) ₹20

Correct Answer: A
Explanation:

For 10 km, total charge is ₹105. Fixed charge = 105 - 10(10) = ₹5.

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Question (33)
QN0036603
The ratio of incomes of two persons is 5 : 4. If their total income is ₹36,000, the first person's income is:
  • (A) ₹16,000
  • (B) ₹18,000
  • (C) ₹20,000
  • (D) ₹22,000

Correct Answer: C
Explanation:

Total parts = 9. First income = 5/9 × 36000 = ₹20,000.

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Question (34)
QN0036604
A rectangular garden has length 5 m more than its width. If its perimeter is 50 m, its length is:
  • (A) 10 m
  • (B) 12.5 m
  • (C) 15 m
  • (D) 20 m

Correct Answer: C
Explanation:

Let width = x and length = x + 5. Then 2(2x + 5) = 50, giving x = 10 and length = 15 m.

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Question (35)
QN0036605
A fraction becomes 2/3 when 1 is added to both numerator and denominator, and becomes 1/2 when 1 is subtracted from both. The fraction is:
  • (A) 3/5
  • (B) 4/7
  • (C) 5/7
  • (D) 5/8

Correct Answer: C
Explanation:

Let the fraction be x/y. Solving (x + 1)/(y + 1) = 2/3 and (x - 1)/(y - 1) = 1/2 gives x = 5 and y = 7.

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Question (36)
QN0036606
The sum of the digits of a two-digit number is 10. If the number is 18 more than its reverse, the number is:
  • (A) 46
  • (B) 55
  • (C) 64
  • (D) 73

Correct Answer: C
Explanation:

x + y = 10 and (10x + y) - (10y + x) = 18, giving x - y = 2. Hence x = 6 and y = 4, so the number is 64.

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Question (37)
QN0036607
Meena has ₹2000 in ₹50 and ₹100 notes. If she has 25 notes in all, the number of ₹50 notes is:
  • (A) 10
  • (B) 12
  • (C) 15
  • (D) 20

Correct Answer: A
Explanation:

Let the numbers of ₹50 and ₹100 notes be x and y. Then x + y = 25 and 50x + 100y = 2000. Solving gives x = 10.

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Question (38)
QN0036608
A library charges a fixed amount for the first three days and ₹3 for every extra day. If a book kept for 7 days costs ₹27, the fixed charge is:
  • (A) ₹9
  • (B) ₹12
  • (C) ₹15
  • (D) ₹18

Correct Answer: C
Explanation:

Extra days = 7 - 3 = 4. Extra charge = 4 × 3 = ₹12. Fixed charge = ₹27 - ₹12 = ₹15.

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Question (39)
QN0036609
If the equations 2x + 3y = 5 and 4x + ky = 10 are coincident, then k is:
  • (A) 3
  • (B) 4
  • (C) 5
  • (D) 6

Correct Answer: D
Explanation:

The second equation must be twice the first: 4x + 6y = 10. Hence k = 6.

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Question (40)
QN0036610
If 3x + 4y = 12 and 6x + 8y = k represent coincident lines, then k equals:
  • (A) 12
  • (B) 18
  • (C) 24
  • (D) 36

Correct Answer: C
Explanation:

The second equation must be twice the first, so k = 2 × 12 = 24.

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