EWT | Academic Question

Questions
Question (1)
QN0036871
1. In a right-angled triangle, the side opposite the right angle is called the:
  • (A) Base
  • (B) Perpendicular
  • (C) Hypotenuse
  • (D) Altitude

Correct Answer: C
Explanation:

The side opposite the right angle is the hypotenuse.

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Question (2)
QN0036872
2. The line segment joining the observer's eye to the point being observed is called:
  • (A) Horizontal line
  • (B) Line of sight
  • (C) Vertical line
  • (D) Transversal

Correct Answer: B
Explanation:

The line joining the observer's eye and the object being viewed is called the line of sight.

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Question (3)
QN0036873
3. When an object is above the horizontal level of an observer's eye, the angle formed by the line of sight with the horizontal is called:
  • (A) Angle of depression
  • (B) Right angle
  • (C) Angle of elevation
  • (D) Complementary angle

Correct Answer: C
Explanation:

The angle between the horizontal line and the line of sight when the object is above the observer is the angle of elevation.

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Question (4)
QN0036874
4. When an object is below the horizontal level of an observer's eye, the angle formed by the line of sight with the horizontal is called:
  • (A) Angle of elevation
  • (B) Angle of depression
  • (C) Angle of reflection
  • (D) Angle of incidence

Correct Answer: B
Explanation:

The angle between the horizontal and the downward line of sight is called the angle of depression.

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Question (5)
QN0036875
5. In a right triangle representing the height and distance of a vertical object, which trigonometric ratio directly relates height and horizontal distance?
  • (A) sin θ
  • (B) cos θ
  • (C) tan θ
  • (D) sec θ

Correct Answer: C
Explanation:

tan θ = Perpendicular/Base = Height/Horizontal distance.

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Question (6)
QN0036876
6. A tower is 20 m high. If the angle of elevation of its top from a point on the ground is 45°, the distance of the point from the tower is:
  • (A) 10 m
  • (B) 20 m
  • (C) 20√3 m
  • (D) 40 m

Correct Answer: B
Explanation:

tan 45° = 20/d, so d = 20 m.

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Question (7)
QN0036877
7. A vertical pole is 12 m high. If the angle of elevation of its top is 30°, the horizontal distance of the observer from the pole is:
  • (A) 12 m
  • (B) 12√3 m
  • (C) 6√3 m
  • (D) 24 m

Correct Answer: B
Explanation:

tan 30° = 12/d. Thus d = 12√3 m.

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Question (8)
QN0036878
8. A tower is 15 m high and its top is observed at an angle of elevation of 60°. The distance of the observer from the tower is:
  • (A) 15 m
  • (B) 15√3 m
  • (C) 5√3 m
  • (D) 5 m

Correct Answer: C
Explanation:

tan 60° = 15/d, so d = 15/√3 = 5√3 m.

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Question (9)
QN0036879
9. A 10 m high pole subtends an angle of elevation of 45° at a point on the ground. The distance of the point from the pole is:
  • (A) 5 m
  • (B) 10 m
  • (C) 10√3 m
  • (D) 20 m

Correct Answer: B
Explanation:

tan 45° = 10/d, hence d = 10 m.

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Question (10)
QN0036880
10. An observer's eye is 1.5 m above the ground. The observer is 20 m from a tower and sees its top at an elevation of 45°. The height of the tower is:
  • (A) 20 m
  • (B) 21.5 m
  • (C) 18.5 m
  • (D) 22 m

Correct Answer: B
Explanation:

Height above eye level = 20 tan 45° = 20 m. Therefore, tower height = 20 + 1.5 = 21.5 m.

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