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Height above eye level = 30 tan 30° = 10√3 m. Hence total height = 10√3 + 1.6 m.
sin 30° = 6/L, so L = 12 m.
Height = 10 sin 60° = 10 × √3/2 = 5√3 m.
Horizontal distance = 8 cos 60° = 4 m.
sin 60° = 5√3/L, giving L = 10 m.
Height = 10 tan 45° = 10 m.
Height = 10√3 tan 30° = 10√3 × 1/√3 = 10 m.
tan 60° = 20/d, so d = 20/√3 m.
Shadow is proportional to cot θ. Therefore, the ratio is cot 30°/cot 60° = 3, so the new shadow is 3x.
Tower height = 12 m. At 60°, shadow = 12/√3 = 4√3 m.
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